Answer: Therefore, the measure of arc EAB is 148 degrees and option C is the correct choice.
That’s what I think, sorry if it’s not correct
Answer:
89,400 was the population in 2016
Step-by-step explanation:
I have attached a screenshot with the complete question
Part (1):We are given the prototype used for building the wall with the following dimensions:
long side = 8 in
short side = 5 in
Now, in the wall itself, we want to find the value of the length "a".
This length represents the short side in the prototype used in building the wall.
Therefore:
a = 5 in
Part (2):We are given the prototype used for building the wall with the following dimensions:
long side = 8 in
short side = 5 in
Now, in the wall itself, we want to find the value of the length "b".
This length represents the long side in the prototype used in building the wall.
Therefore:
b = 8 in
Part (3):Looking at Dakota's wall, we can note that its height is formed from three bricks each having the height "b". We have deduced previously that b = 8 in.
Therefore:
height of wall = 3 * b
height of wall = 3 * 8 = 24 in
Part (4):Looking at Dakota's wall, we can note that its length is formed from nine bricks each having a length "a". We have deduced previously that a = 5 in.
Therefore:
length of wall = 9 * a
length of wall = 9 * 5 = 45 in
Hope this helps :)
Answer: He made $90 last week.
Assumption :
Let, Luis made $X last week.
He made $72 this week which is 80% of $X that he made last week
⇒ X * 80% = 72
⇒ X * 80/100 = 72
⇒ X = (72 * 100)/80
⇒ X = 90
Therefore, he made $90 last week.
To remember :
While solving this type of problems, be careful to understand which one of last time and current time is not given; just assume that one and input other conditions, the problem will be solved.
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.