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photoshop1234 [79]
3 years ago
9

In the diagram below, segment DG is Perpendicular to segment DF

Mathematics
1 answer:
daser333 [38]3 years ago
4 0
What is he saying he was a
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A system of two linear equations is graphed on a coordinate plane. If the system of equations has no solutions
scoray [572]

Answer:

see explanation

Step-by-step explanation:

The solution to the equations is at the point of intersection of the 2 lines.

If the system has no solution, this indicates the lines do not intersect and therefore must be parallel.

5 0
3 years ago
Which pair of equations can be used to solve for x in PQR?
almond37 [142]

Answer:

A

Step-by-step explanation:

sin57° = \frac{opposite}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

∠ P = 180° - (90 + 57)° ← sum of angles in triangle

∠ P = 180° - 147° = 33° , then

cos33° = \frac{adjacent}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

Thus the 2 ratios used to solve for x are A

7 0
3 years ago
(-1/8c+16)-(3/8+3c) difference
zloy xaker [14]

Answer:

-25 (c-5) / 8

Negative 25 (c-5) over 8

5 0
3 years ago
Read 2 more answers
A baseball player hit 65 home runs in a season. Of the 65 home​ runs, 19 went to right​ field, 23 went to right-center​ field, 9
olchik [2.2K]

Answer:

a) 29.23% probability that a randomly selected home run was hit to right field

b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.

(a) What is the probability that a randomly selected home run was hit to right field?

Desired outcomes:

19 home runs hit to right field

Total outcomes:

65 home runs

19/65 = 0.2923

29.23% probability that a randomly selected home run was hit to right field

(b) Was it unusual for this player to hit a home run to right field?

29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

8 0
4 years ago
I need help with this problemmm, someone help mee!!.
Varvara68 [4.7K]

Answer:

∠A=30°

Step-by-step explanation:

let's call the angle at the bottom B and the one next to the 130 C

∠A=3x-6

∠C=180-130= 50°

vertical angles are equal∠B =8x+4

∠A+∠C+∠B=180°

find x:

3x-6+50+8x+4= 180°

11x+48=180°

11x= 132

x=12

find ∠A

∠A=3x-6= 3(12)-6 =30°

5 0
3 years ago
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