Answer:
The displac ment between t = 1 and t = 4 is 272 feet
Step-by-step explanation:
To get the displacement of the ball, we first need to get the equation for the position of the ball with respect to time.
We can do this by differentiating the velocity equation given:
v(t) = -32t +96
integrating between the limits of t = 1 and t = 4, we have
![s =[ -16t^2 +96t] t = 4, t =1](https://tex.z-dn.net/?f=s%20%3D%5B%20-16t%5E2%20%2B96t%5D%20t%20%3D%204%2C%20t%20%3D1)
where t = 4.
s = 256 + (96) =352 feet
Where t = 1
s = 80
Displacement of the ball = 352 -80 = 272ft
The displac ment between t = 1 and t = 4 is 272 feet
Answer:
8
Step-by-step explanation:
2:9
9*4 = 36
2*4 = 8
Don’t worry bro, just take breaks and do whatever you find interesting. If your going through problems. I suggest you to talk with someone you trust!!!
Answer:
The ladder is not safe at this height. The height from ground to top of the ladder is < 11.6 ft for safety reasons and this can be determined by using trigonometry functions.
Step-by-step explanation:
The ladder is not safe at this height. The height from ground to top of the ladder is < 11.6 ft for safety reasons and this can be determined by using trigonometry functions.
Given :
Joshua has a ladder that is 12 ft long.
He wants to lean the ladder against a vertical wall so that the top of the ladder is 11.8 ft above the ground.
For safety reasons, he wants the angle the ladder makes with the ground to be no greater than 75°.
Check the angle that the ladder makes with the ground:
The ladder is safe when the angle the ladder makes with the ground to be no greater than 75° but is so, the ladder won't be safe.
To make the ladder safe, the height should not be 11.8ft.
The height from ground to top of the ladder is < 11.6 ft for safety reasons.
If i used the correct numbers for the base and the height the area of the triangle would be 182
