Which graph represents y = [x] over the domain 2<2<5?

Consider the number line of x > 28 which numbers are solutions of the inequality

Gelneren [198K]

Answer:

D and E because they are bigger than 28. C is 28 but there isn't a greater OR EQUAL sign next to it

8 0

3 years ago

¿Cuál es el área de un rectángulo, sabiendo que su perímetro mide 24 cm y que su base es el triple de su altura?

Brrunno [24]

Answer:

El área del rectángulo es:

27 cm²

Step-by-step explanation:

Consideración:

La formula del perímetro de un rectángulo es:

p = 2(altura + base)

Planteamiento:

24 = 2(a+b)

b = 3a

a = longitud de la altura del rectángulo

b = longitud de la base del rectángulo

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

24 = 2(a + 3a)

24/2 = 4a

12 = 4a

a = 12/4

a = 3 cm

de la segunda ecuación del planteamiento:

b = 3a

b = 3*3

b = 9 cm

Comprobación:

de la primer ecuación del planteamiento:

24 = 2(3+9)

24 = 2*12

Respuesta:

la formula del área de un rectángulo es:

A = base * altura

A = 9cn * 3cm

A = 27cm²

5 0

3 years ago

Suppose p(a) = 0.40 and p(a 

sveticcg [70]

Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

$P(A\cup B)+P(A\cap B)=P(A)+P(B)$

For parts (a) and (b), you're given everything you need to determine $P(B)$ .

For part (c), if $A$ and $B$ are mutually exclusive, then $P(A\cap B)=0$ , so $P(A\cup B)=P(A)+P(B)$ . If the given probability is $P(A\cup B)=0.55$ , then you can find $P(B)=0.15$ . But if this given probability is for the intersection, finding $P(B)$ is impossible.

For part (d), if $A$ and $B$ are independent, then $P(A\cap B)=P(A)\cdot P(B)$ .

8 0

3 years ago

The fish population in a certain lake rises and falls according to the formula F = 3000(23 + 11t − t2). Here F is the number of

Gemiola [76]

Answer:

a) On January 1, 2017 the fish population will be the same as the initial population.

b) On September 18th, 2018 the fish population will be zero.

Step-by-step explanation:

Hi there!

a) First, let´s write the function:

F(t) = 3000(23 + 11t − t²)

The population on January 1, 2006 is the population at t = 0. Then:

F(0) = 3000(23 + 11· 0 - 0²)

F(0) = 3000 · 23 = 69000

This will be the population every time at which t² - 11t = 0. Then let´s find the other value of t (besides t = 0) that makes that expression to be zero:

t² - 11t = 0

t(t - 11) = 0

t = 0

and

t - 11 = 0

t = 11

On January 1, 2017 (2006 + 11), the fish population will be the same as the initial population.

b) We have to obtain the value of t at which F(t) = 0

F(t) = 3000(23 + 11t − t²)

0 = 3000(23 + 11t − t²)

divide both sides of the equation by 3000

0 = 23 + 11t − t²

Let´s solve this quadratic equation using the quadratic formula:

a = -1

b = 11

c = 23

x = [-b ± √(b² - 4ac)] / 2a

x = 12.8 ( the other value of x is negative and therefore discarded).

After 12.8 years all the fish in the lake will have died.

If 1 year is 12 months, 0.8 years will be:

0.8 years · 12 months/year = 9.6 months

If 1 month is 30 days, 0.6 month will be:

0.6 month · 30 days / month = 18 days

All the fish will have died after 12 years, 9 months and 18 days from January 1, 2006. That is, on September 18th, 2018.

7 0

3 years ago

Find the area, a rectangle with a length of 4 cm and a width of 2.5 cm

Brums [2.3K]

Answer:

10

Step-by-step explanation:

4x2.5=10CM2

the area of a rectangular =width multiply its length

5 0

1 year ago

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