Let's begin with <span>f(x) = a(x-h)^2+ k. Note that we must use "^" to indicate exponentiation. Write (x-h)^2, not (x-h)2.
If (-3,4) is the vertex, then the above equation becomes f(x) = a(x-[-3])^2 + 4, or
f(x) = a(x+3)^2 + 4. We are told that the graph passes through (-1,0), so must now substitute those coordinates into the above equation:
f(-1) = a([-1]+3)^2 + 4 = 0 (0 is the value of f when x is -1)
Then we have a(2)^2 + 4 =0, or 4a + 4 = 0. Thus, a = -1.
The equation of this parabola is now f(x) = -(x+3)^2 + 4.
Write it in "standard form:" f(x) = -(x^2 + 6x + 9) + 4, or
f(x) = -x^2 - 6x - 9 + 4, or
answer => f(x) = -x^2 - 6x - 5 = ax^2 + bx + c
Thus, a=-1, b=-6 and c= -5.</span>
Answers:
4; 20; 3x² - 4x + 3; 52; 17
Step-by-step explanation:
f(-1): replace x in f(x) = x² + 3 with -1: f(-1) = (-1)² + 3 = 4
f(-4) + g(-1) = (-4)² + 3 + <em>2(-1) + 3</em> = 16 + 3 <em>- 2 + 3</em> = 20 <em>(since g(x) = 2X + 3)</em>
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3f(x) - 2g(x) = 3[x² +3] - 2[2x + 3} = 3x² + 9 - 4x - 6 = 3x² - 4x + 3
f(g(2)): First, evaluate g(2). It is g(2) = 2(2) + 3 = 7. Next, use this output, 7, as the input to f(x): f(g(x)) = (7)² + 3 = 49 + 3 = 52
g(f(2)): First, evaluate f(x) at x = 2: f(2) = (2)² + 3 = 7. Next, use this 7 as the input to g(x): g(f(2)) = g(7) = 2(7) + 3 = 17
1) (m-n)(m+n)
= m^2 +mn-nm-n^2
= m^2-n^2
2) (z-3)(z+3)
= z^2+3z-3z-9
= z^2-9
I am not sure but the answer should be 52.4.
Answer:
What were is it
Step-by-step explanation: