Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
We have to sum 8 and two-third of x, so we must multiply x by 2/3 and sum it with 8,
thus, the expression is
High temperatures were recorded for 30 consecutive days: 50, 45, 49, 50, 43, 49, 50, 49, 45, 49, 47, 47, 44, 51, 51, 44, 47, 46,
Simora [160]
The answer is 21, you subtract the smallest number (30) by the biggest number (51)
It's diameter is 17.98. (I'm pretty sure I'm right I even used a calculator, if not sorry)
Answer:
6 and 10
Step-by-step explanation:
xy=60
2(x+y)=32
x+y=16
y=16-x
Substitute y into area equation
x(16-x)=60
16x-x^2=60
x^2-16x+60=0
(x-10)(x-6)=0
x=10, 6
y=6, 10
