I need help with this simple Geometry Question

Mathematics

1 answer:

Nostrana [21]3 years ago

8 0

Answer: 132º

Step-by-step explanation:

Since <QSR is an inscribed angle, that means that the intercepted arc, which is arc QR, is twice the measure of that angle, which is 132º. Since <QPR is a center angle, it is equal to its center arc. So, <QPR is 132º.

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dimaraw [331]

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3 years ago

What is the value of x -6/7=-x/84?

AURORKA [14]

Answer:

x = 72 / 85

Step-by-step explanation:

x -6/7=-x/84

x + x/84 = 6/7

84/84x + 1/84x = (12*6) / (12*7)

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Multiply left and right from the = sign by 84/85 and you do that so you get a division ON THE LEFT SIDE that equals as 1... See how it works:

84/85 * { 85/84 } * x = 84/85 * { ( 72 ) / ( 84 ) }

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6 0

3 years ago

Make r the subject of the formula <br>v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h) <br>

mel-nik [20]

Answer:

$\boxed{r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } }$

Step-by-step explanation:

$Solve \: for \: r: \\ = > v= \pi {h}^{2}(r - \frac{h}{3} ) \\ \\ v=\pi {h}^{2}(r - \frac{h}{3} )is \: equivalent \: to \: {h}^{2}\pi(r - \frac{h}{3} ) = v: \\ = > {h}^{2}\pi(r - \frac{h}{3} ) = v \\ \\ Divide \: both \: sides \: by \: \pi {h}^{2} : \\ = > r - \frac{h}{3} = \frac{v}{\pi {h}^{2} } \\ \\ Add \: \frac{h}{3} \: to \: both \: sides: \\ = > r = \frac{h}{3} + \frac{v}{\pi {h}^{2} }$