I need help with this simple Geometry Question

Mathematics

1 answer:

Nostrana [21]2 years ago

8 0

Answer: 132º

Step-by-step explanation:

Since <QSR is an inscribed angle, that means that the intercepted arc, which is arc QR, is twice the measure of that angle, which is 132º. Since <QPR is a center angle, it is equal to its center arc. So, <QPR is 132º.

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What reasoning and explanations can be used when solving radical equations and how do extraneous solutions arise from radical eq

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Answer:

We know that, a 'radical equation' is an equation that contains radical expressions, which further are the expressions containing radicals ( square roots and other roots of numbers ).

In order to solve radical equations, we use the rules of exponents and basic algebraic properties.

The common reasoning to use while solving a radical equation is:

1. Isolate the radical expression.

2. Square both sides of the equation to remove radical.

3. After removing the radical, solve the equation to find the unkown variable

4. Check the answer for the errors occurred by removing the radicals.

For e.g. $\sqrt{x}-3=5$

i.e. $\sqrt{x}-3+3=5+3$ ( Adding 3 on both sides )

i.e. $\sqrt{x}=8$

i.e. $(\sqrt{x})^{2} =8^{2}$

i.e. $x=64$ .

So, the solution the the radical equation $\sqrt{x}-3=5$ is x = 64.

Further, we know that an 'extraneous solution' is that root of the radical equation which is not a root of the original equation and is excluded from the domain.

for e.g. Take $\sqrt{x+4} =x-2$