What are the coordinates of the midpoint of this<br> segment?<br> Type them into the table below

You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e

victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = $\dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}$

mean = 15.58

the standard deviation $\sigma$ = $\sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}$

the standard deviation = $\sqrt{\dfrac{(26.2 - 15.58)^2 +(27.7 - 15.58)^2 +(8.6 - 15.58)^2 + (3.8 - 15.58)^2 + (11.6 - 15.58)^2 }{5 } }$

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df at 4 and 80% confidence level, the critical value t from t table = 1.533

The Margin of Error M.O.E = $t \times \dfrac{\sigma}{\sqrt{n}}$

The Margin of Error M.O.E = $1.533 \times \dfrac{9.62297}{\sqrt{5}}$

The Margin of Error M.O.E = $1.533 \times 4.3035$

The Margin of Error M.O.E = 6.60

The Confidence interval = ( $\mu \pm M.O.E$ )

The Confidence interval = ( $\mu + M.O.E$ , $\mu - M.O.E$ )

The Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The Confidence interval = (8.98 , 22.18)

7 0

3 years ago

Bob discovers a box with 30 identical, used, rechargeable batteries in his attic.

monitta

Answer:

a) All of them are out of charge = 9.31x10⁻¹⁰

b) 20% of them are out of charge = 5.529x10⁻⁴

Step-by-step explanation:

This problem can be modeled as a binomial distribution since

There are n repeated trials and all of them are independent of each other.

There are only two possibilities: battery is out of charge and battery is not out of charge.

The probability of success does not change with trial to trial.

Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50

P = 0.50

1 - P = 0.50

a) All of them are out of charge?

Probability = nCx * P^x * (1 - P)^n-x

Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰

Probability = 9.31x10⁻¹⁰

b) 20% of them are out of charge?

0.20*30 = 6 batteries are out of charge

Probability =₃₀C₆(0.50)²⁴(0.50)⁶

Probability = 5.529x10⁻⁴

5 0

3 years ago

it took 8 hours for karl and lou to finish a project for science class together. if karl had worked alone on the project it woul

kkurt [141]

It would take 10 hours just like it did for Karl .

4 0

4 years ago

Find the rate of change for the interval [5,15]

Aleks04 [339]

Left side goes up 5 right side goes up 7

The rate of change between 5,15 is 10

3 0

3 years ago

What number must you add to complete the square? <br><br> x2 + 12x = -5

VARVARA [1.3K]

You must add 6 to complete the square.
x^2+12x+(6)=-5(6)

7 0

3 years ago

What are the coordinates of the midpoint of this segment? Type them into the table below