87.5
Tall. /. Shadow
3 / 1.74=. X /. 50.75
Cross multiply
152.25= 3x
Divide by 3
X= 87.5
The distance flown by plane is 750 kilometers.
Step-by-step explanation:
Let,
Distance traveled by plane = x
Distance traveled by car = y
Total distance = x+y
According to given statement;
The distance by car was 125 kilometers less than the distance by plane.
y = x - 125 => x=y+125 Eqn 1
The total distance was 500 kilometers less than three times the distance traveled by car.
Total distance = 3y - 500
x+y=3y-500 Eqn 2
Putting value of x from Eqn 1;
Putting y=625 in Eqn 1
The distance flown by plane is 750 kilometers.
Keywords: linear equations, substitution method
Learn more about linear equations at:
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Adjacent angles are supplementary
so the exterior angles = 180 - 84 = 96 segrees.
The recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5
<h3>How to determine the recursive formula?</h3>
The function is given as:
h(n) = 41- 5n
Calculate h(1) and h(2)
h(1) = 41- 5(1)
h(1) = 36
h(2) = 41- 5(2)
h(2) = 31
Calculate the difference between h(1) and h(2)
d = 31 - 36
d = -5
This means that:
h(1) = 36 and h(n) = h(n -1) - 5
Hence, the recursive formula of h(n) is h(1) = 36 and h(n) = h(n -1) - 5
Read more about recursive formula at:
brainly.com/question/1275192
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Step-by-step explanation:
The data below is what was provided in the question and it is what I solved the question with
P(A1) = 0.23
P(A2) = 0.25
P(A3) = 0.29
P(A1 n A2 ) = 0.09
P(A1 n A3) = 0.11
P(A2 n A3) = 0.07
P(A1 n A2 n A3) = 0.02
a
P(A2|A1) = P(A1 n A2)/P(A1)
= 0.09/0.23
= 0.3913
We have 39.13% confidence that event A2 will occur given that event A1 already occured
b.)
P(A3 n A3|A1) = P(A2 n A3)n A1)/P(A1)
= 0.02/0.23
= 0.08695
We have about 8.7% chance of events A2 and A3 occuring given that A1 already occured.
C.
P(A2 u A3|A1)
= P(A1 n A2)u(A1 n A3)/P(A1)
= P( A1 n A2) + P(A1 n A3) - P(A1 n A2 n A3) / P(A1)
= (0.09+0.11-0.02)/0.23
= 0.18/0.23
= 0.7826
We have 78.26% chance of A2 or A3 happening given that A1 has already occured.
