Answer:
- 33 1/3 liters of 30%
- 16 2/3 liters of 45%
Step-by-step explanation:
Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...
0.45x +0.30(50 -x) = 0.35(50)
0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)
x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl
33 1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.
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<em>Comment on the solution</em>
You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...
(mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3
Answer:
0.375
Step-by-step explanation:
You mean 3/8 right?
3/8=0.375
Answer:
x = -3±i sqrt(2)
Step-by-step explanation:
x^2+6x + 11 =0
Subtract 11 from each side
x^2+6x + 11-11 =0-11
x^2+6x =-11
Take the coefficient of the x terms
6
Divide by 2
6/2 =3
Square it
3^2 =9
Add it to each side
x^2+6x + 9 =-11+9
x^2 + 6x+9 = -2
The left hand side becomes (x+ (6/2) )^2
(x+3)^2 = -2
Take the square root of each side
sqrt((x+3)^2) = ±sqrt(-2)
x+3 = ±sqrt(-2)
x+3= ±i sqrt(2)
Subtract 3 from each side
x+3-3 = -3±i sqrt(2)
x = -3±i sqrt(2)
