Answer:
Let the three consecutive integers be x,x+1,x+2
ATQ
x+2(x+2)+15=4(x+1)
=3x+19=4x+4
= x=15
..... Hence. The nos. Are 15,15+1=16 and 15+2=17
Step-by-step explanation:
y+3 = -6(x+9)
m(x-x1)= (y-y1)
-6[x-(-9)] = [y-(-3)]
-6(x+9) = y+3
.....