The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²

This is found by dividing 32 by 2.4
Answer:
x-intercept = (18/5,0)
y-intercept = (0,-2)
Step-by-step explanation:
I graphed it and found the intercepts
brainliest would be great
Answer:
5
Step-by-step explanation:
4 7/12 + 5/12 = 4 12/12 which equals 5
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />