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3 years ago

The profit P (in dollars) from selling x calculators is P=25x-10x+250. How many calculators are sold when the profit is $430?

Mathematics

1 answer:

Sonja [21]3 years ago

4 0

Answer:

Step-by-step explanation:

425=25x-10x-250

675=15x

x=45

45 calculators were sold.

Mark brainliest please if this answer work please

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What is the equation of the line that passes through the points (-4,8) and (2,-1)

DiKsa [7]

Answer:

y - 8 = (3/2)(x + 4)

Step-by-step explanation:

As we move from (-4, 8) to (2, -1), x increases by 6 (this is the run) and y decreases by 9 (this is the "rise"). Thus, the slope is

m = rise / run = 9/6, or 3/2.

Using the point-slope form of the equation of a straight line, we get:

y - 8 = (3/2)(x + 4)

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3 years ago

A line passes through (-2,5) and has slope. What is an equation of the line in point-slope form?

shepuryov [24]

Answer:

Step-by-step explanation:

since the question does not have a given slope you can just put the point into the point slope formula y-y1 = m(x-x1)

y-5 = m(x-(-2))

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3 years ago

Does anyone know how to do this?

sineoko [7]

Answer:

$\boxed{\tt x=\sqrt{85} }$

Step-by-step explanation:

When making a right triangle with 2 points, the distance is the hypotenuse which can be represent as "x"

To find the distance we can use the Pythagorean theorem.

$\boxed{{\tt a^2+b^2=c^2}}$

→ $\tt a=9$

→ $\tt b=2$

→ $\tt c=x$

Let's Plug in the side lengths:

$\tt 9^2+2^2=x^2$

Evaluate 9²= 81 and 2²= 4:

$\tt 81+4=x^2$

Now, add 81+4= 85

$\tt 85=x^2$

Take the square root of both sides:

$\tt x=\sqrt{85}$

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3 years ago

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3 years ago

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>

6 0

4 years ago

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