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icang [17]
3 years ago
8

On the Audio Tools contextual tab, which tab will control how the audio file appears, if it appears, on the slide itself?

Computers and Technology
2 answers:
ohaa [14]3 years ago
4 0

Answer:

C. Format

Explanation:

Bookmarks are for future reference, playback is for listening and scrolling through your project, and design, it's basically what it says, designing.

Formating is the size of the video, the frame, how and if it appears, and the actual timeline and video/audio/ogg file or mp3 itself.

from an after effects user.

and a semi music designer that uses audacity.

I hope this helps :)

dexar [7]3 years ago
3 0

Answer:

B.

Explanation:

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A pair of single quotes ' will prevent the shell from interpreting any special character. True or False
Stells [14]

Answer:

The answer is "True".

Explanation:

A single quote is a punching mark also known as an apostrophe located on the US Standard keyboard near the Enter button.

  • It's also known as a direct quote, such markings are also used in a news article for marking a statement. If a paragraph is a capital letter within the next quote, it is a function of a single quote. It refers to verbal marks.
  • A couple of quotes will avoid a unique character becoming interpreted by only the shell, that's why the given statement is true.
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ale4655 [162]

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Windows start November 20, 1985

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MyProgramming Lab
Akimi4 [234]

Answer:

Explanation:

The following code is written in Python. It creates a method for each one of the questions asked and then tests all three with the same test case which can be seen in the picture attached below.

def alternating_list(lst1, lst2):

   lst3 = []

   for x in range(len(lst1)):

       lst3.append(lst1[x])

       try:

           lst3.append(lst2[x])

       except:

           pass

   if len(lst2) > len(lst1):

       lst3.extend(lst2[len(lst1):])

   return lst3

def reverse_alternating(lst1, lst2):

   lst3 = []

   if len(lst1) == len(lst2):

       for x in range(len(lst1) - 1, -1, -1):

           lst3.append(lst1[x])

           lst3.append(lst2[x])

   return lst3

def alternating_list_no_extra(lst1, lst2):

   lst3 = []

   max = 0

   if len(lst1) > len(lst2):

       max = len(lst2)

   else:

       max = len(lst1)

   for x in range(max):

       lst3.append(lst1[x])

       try:

           lst3.append(lst2[x])

       except:

           pass

   return lst3

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Mattias's friend asked him to critique his presentation about gorillas. Mattias noticed that there weren't any images of gorilla
Deffense [45]

Answer:

c

Explanation:

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