do you want us to write something about it or??
Answer:
3.59 minutes
Explanation:
We solve this question using z score formula
Using Excel
Z-SCORE= (DataPoint-AVERAGE(DataSet))/STDEV(DataSet)
IN EXCEL,
AVERAGE, an excel function that calculates the Average of data set
STDEV.S: calculates the standard deviation while treating the data as a ‘sample’ of a population.
STDEV.P: This function calculates the standard deviation while treating the data as the entire population.
Z score formula = x - μ/σ
x = ?? μ = 2.5 minutes σ = 0.5 minutes
We are asked : If 1.5% of the callers are put on hold for longer than x minutes, what is the value of x?
Hence, Longer than = Greater than =
100 - 1.5%
= 100 - 0.015
= 0.985 ( 98.5%)
Using Excel we calculate = z score for 98.5 percentile
= 2.1701
Z score = x - μ/σ
2.1701 = x - 2.5/0.5
2.1701 × 0.5 = x - 2.5
1.08505 = x - 2.5
x = 1.08505 + 2.5
x = 3.58505
Approximately to 2 decimal places = 3.59 minutes
Therefore, 1.5% of the callers are put on hold for longer than 3.59 minutes.
Answer:
Yes, it can be determined if an an external web site was likely accessed from a computer in the same department a couple of seconds ago.
Explanation:
Yes. “Dig” can be used to search that website in the local DNS server. A practical example would be to insert “dig google.com” and that will give us the result of the query time for searching and finding google.com. Supposing google.com was accessed a few seconds ago, then an entry for google.com is cached in the local DNS cache and the search or query time is 0 msec. If not the query time will be large.
Input devices are things that receive info, such as mice, a keyboard, microphone etc.
Output devices are things that allow the computer to express info, such as a monitor, speaker, headphones, etc
