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liq [111]
3 years ago
11

Picture is shown abovesuppose that y varies directly with x, and y=12 when x=15​

Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0

Answer:

y is directly proportional to x

<u>y=kx</u>, where k is a constant

Now, y=12 when x=15

12 = k \times 15 \\ k =  \frac{12}{15}  \\  \boxed{k = 0.8}

When x=2,

y = 0.8 \times 2 \\  \boxed{y = 1.6}

<h3><em><u>Equation: y=</u></em><em><u>kx</u></em></h3><h3><em><u> y: 1.6</u></em></h3>
a_sh-v [17]3 years ago
7 0

Step-by-step explanation:

Since y is directly proportional to x,

we have y = kx, where k is a real constant.

When x = 15, y = 12.

=> (12) = k(15), k = 0.8.

Therefore we have y = 0.8x.

When x = 2, y = 0.8(2) = 1.6.

The answer is y = 1.6 when x = 2.

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