Are the triangles named below congruent? Justify your answer. AABC AAED

Mathematics

2 answers:

anyanavicka [17]3 years ago

5 0

Yes by either SSS or SAS

Anni [7]3 years ago

4 0

Yes, sides AC and AD are congruent and lines BC and DE are also congruent. They also share angle A and bc of the SSA congruence Theorem that means they are congruent.

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Please find the value of this one expression

Masja [62]

Answer:

Solving the expression $\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)$ we get 6

The answer is 6.

Step-by-step explanation:

We need to find value of expression: $\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)$

We know that $\sqrt{81}=9$

Our expression will become

$\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{9 } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-2 -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-4)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4$

We can write $\sqrt[6]{8}=(2^3)^{\frac{1}{6}}=(2)^{\frac{3}{6}}=2^\frac{1}{2}=\sqrt{2} \\$

Now, replacing $\sqrt[6]{8}=\sqrt{2}$

$=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4\\=\frac{2}{\sqrt{2} }.\sqrt{2}+4\\=2+4\\=6$

So, solving the expression $\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)$ we get 6

3 0

3 years ago

Each of Hashim's comedy shows lasts for 75 minutes. He tells an average of 8 jokes every minute. How many of Hashim comedy shows

Setler79 [48]

Hashim's comedy lasts 75 minutes each time
He tells 8 jokes every minute

75 x 8 = 600

He tells ~600 jokes each time

2400/600 = 4

Hashim's viewers will have to see 4 "Hashim comedy shows" episodes to hear 2400 jokes

hope this helps

6 0

3 years ago

Use I = PRT to solve. (time in years)

vivado [14]

Simple interest is $ 9

Solution:

Given that,

P = $ 400

$R = 9 \% = \frac{9}{100} = 0.09$