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2 years ago

What is the perimeter of a rectangle (6in and 4in)

Mathematics

1 answer:

Ghella [55]2 years ago

6 0

The perimeter of the rectangle is 20 in.

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If triangle RST is within Quadrant 4 and cos R= √3/2, what is the value of cotR

Nesterboy [21]

Answer:

CotR = -√3

Step-by-step explanation:

In the 4th quadrant, sin is negative;

Since Cos R = √3/2,

Adjacent = √3

Hypotenuse = 2

Get the opposite;

opp^2 = 2^2 -(√3)^2

opp^2 = 4 - 3

opp^2 = 1

Opp = 1

Get sinR

Sin R = opp/hyp

SinR= -1/2

CotR = cosR/sinR

CostR = (√3/2)/(-1/2)

CotR = √3/2* -2/1

CotR = -√3

6 0

2 years ago

Tracy has a cell phone plan that provides 250 free minutes each month for a flat rate of $29.

natali 33 [55]

Answer:

250 minutes with the flat rate of $29.

$x\leq 250$

x would be the number of minutes called.

$x-250$

Tracy would be charged by $0.35 per minute.

$f(x)=29\\ 0\leq x\leq 250$

$f(x)=0.35(x-250)+29,\\250\leq x\leq ∞$

6 0

2 years ago

Need help with this one also

-Dominant- [34]

Answer:

Step-by-step explanation:

10/7 = 1.4285

9/y = 1.4285

Multiply both sides by y.

9 = 1.4285y

Divide both sides by y.

6.3 = y

6 0

2 years ago

If f(x) = 5x - 12, what is f2)? O A. -22 O B. 10 O C. -2 D. 2

Step2247 [10]

Answer:

C , -2

Step-by-step explanation:

Replace X in the equation with 2

f(2) = 5(2) - 12

f(2) = 10-12

f(2) = -2

6 0

3 years ago

Read 2 more answers

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

1 year ago