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2 years ago

What is the perimeter of a rectangle (6in and 4in)

Mathematics

1 answer:

Ghella [55]2 years ago

6 0

The perimeter of the rectangle is 20 in.

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Kent mixed oil and gas for his lawn mower. He mixed 8 fluid ounces of oil for every 1 gallon of gas. Which of the following stat

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Answer:

Step-by-step explanation:

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3 years ago

Jamisha is solving the equation 4 ( x − 2 ) = 34 for x . Her work is shown in the table.

shtirl [24]

Answer:

Step-by-step explanation:

4x -8 = 34

4x = 42

x = 42/4 = 21/2 = 10.5

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3 years ago

What can be constructed from polygons alone?

UkoKoshka [18]

Cone (not including the vertex)

Cylinder

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2 years ago

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

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3 years ago

ILL GIVE BRAINLIEST

labwork [276]

Answer:

I can't read the question it's too blurry

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2 years ago