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Vesnalui [34]
2 years ago
12

What is the answer in scientific notation

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
5 0
The answer would be 3 times 10^-5
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What is the length of AC? What is the measure of angle A? What is the measure of angle B?
kipiarov [429]

Answer/Step-by-step explanation:

✔️Find AC using Pythagorean Theorem:

AC² = 25.2² - 11.3²

AC² = 507.35

AC = √507.35

AC = 22.5 (nearest tenth)

✔️Find m<A using trigonometric ratio:

Reference angle = A

Opp = 11.3

Hyp = 25.2

Sin(A) = opp/hyp

Sin(A) = 11.3/25.2

A = sin^{-1}(11.3/25.2)

A = 26.6° (nearest tenth)

✔️Find m<B using trigonometric ratio:

Reference angle = B

Adj = 11.3

Hyp = 25.2

Cos(A) = adj/hyp

Cos(A) = 11.3/25.2

A = cos^{-1}(11.3/25.2)

A = 63.4° (nearest tenth)

6 0
3 years ago
Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab
Leviafan [203]

Answer:

z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936  

The p value can be founded with this formula:

p_v =P(z  

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

\bar X_{1}=7.6 represent the mean for Gibbs products

\bar X_{2}=8.1 represent the mean for the competitor

\sigma_{1}=2.3 represent the population standard deviation for Gibbs

\sigma_{2}=2.9 represent the sample standard deviation for the competitor

n_{1}=40 sample size for the group Gibbs

n_{2}=55 sample size for the group competitor

\alpha=0.05 Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}< 0  

The statistic would be given by:

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

Replacing the info given we got:

z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936  

The p value can be founded with this formula:

p_v =P(z  

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0
3 years ago
Estimate the quotient of 900.37 and 29.8. 3 9 30 90
vesna_86 [32]

Answer:

30

Step-by-step explanation:

Quotient means were dividing, so divide 900.37 by 28.9

900.37/28.9=30 rounded up.

The estimated quotient of 900.37 and 28.9 is 30.

Hope this helps!

7 0
3 years ago
Read 2 more answers
A leaf fell into a river and traveled 140 meters in 4 minutes how many meters did the leaf travel per minute ​
Alekssandra [29.7K]

Answer:

The answer is 35

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
4 The ratio of corresponding dimensions of two similar solids is 3/4. The surface
White raven [17]
4.

The ratio is 3/4 for corresponding dimensions, the ratio of their surface areas is equal to the square of this ratio:

\sf (\dfrac{3}{4})^2=\dfrac{S}{96}

Simplify the exponent:

\sf \dfrac{9}{16}=\dfrac{96}{S}

Cross multiply:

\sf 9S=1536

Divide 9 to both sides:

\sf S\approx 170.7~m^2

So the surface area of the second solid is 54 square meters.

The ratio is 3/4 for corresponding dimensions, the ratio of their volumes is equal to the cube of this ratio:

\sf (\dfrac{3}{4})^3=\dfrac{720}{V}

Simplify the exponent:

\sf \dfrac{27}{64}=\dfrac{720}{V}

Cross multiply:

\sf 27V=46080

Divide 64 to both sides:

\sf V\approx 1706.7~m^3

5.

A globe is a sphere, use the formula for the volume of a sphere:

\sf V=\dfrac{4}{3}\pi r^3

The radius is half of the diameter, so the radius here is 40/2 = 20. Plug it in the formula, use 3.14 to approximate for Pi:

\sf V=\dfrac{4}{3}(3.14)(20)^3

Simplify the exponent:

\sf V=\dfrac{4}{3}(3.14)(8000)

Multiply:

\sf V\approx \boxed{\sf 33,493~in^3}
6 0
4 years ago
Read 2 more answers
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