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3 years ago

If you guys know answer pls

Mathematics

1 answer:

ipn [44]3 years ago

3 0

Answer:

For A: -12
For C: 12

Step-by-step explanation:

For A:

3 × 0 = 0
3 × 4 = 12
Put them together: 0 - 12
0 - 12 = -12

For C:

-4 × 0 = 0
-4 × 3 = -12
Put them together: 0 - (-12)
Simplify: 0 + 12
0 + 12 = 12

For B and D, I'm not sure how to phrase the answer, but with my work, you should be able to do it. If you can't figure out B and D, I'll edit my answer or explain in the comments. I hope this still helps!

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50 points

JulsSmile [24]

Answer:

b. w= 8x^2-2y / y

Step-by-step explanation:

Given:

(2*x^2)/y = (w+2)/4

Isolating w, we get:

w = (8*x^2)/y - 2

Multiplying and dividing the second term in the right-side of the equality by y, we get:

w = (8*x^2)/y - 2*y/y

Subtracting the fractions:

w = (8*x^2 - 2y)/y

7 0

3 years ago

Read 2 more answers

-5+|-15÷(-5) |2(-5)

pav-90 [236]

Answer:

The value of this expression is -35.

Step-by-step explanation:

Let's use the order of operations (PEMDAS), to solve this problem.

$-5+|-15/-5|*2*(-5)\\-5+3*-10\\-5+-30\\-35$

In conclusion, the value of this expression is -35. Hope this helped :D

7 0

3 years ago

Please help I can’t figure this out!

Monica [59]

Explanation:

All values in the x-column get filled with -2.

The graph is the vertical line, x = -2.

You are told x=-2. There is nothing to figure out. The value of y is irrelevant.

That equation describes a vertical line. The points on the line have x-coordinate -2, and any (every) y-coordinate.

4 0

2 years ago

R = sec(θ) − 2cos(θ), where -π/2 < θ < π/2

Alex

Answer:

y = (x/(1-x))√(1-x²)

Step-by-step explanation:

The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:

x = r·cos(θ)

y = r·sin(θ)

x² +y² = r²

r = sec(θ) -2cos(θ)

r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)

r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²

(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations

x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor

y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

$\boxed{y=\dfrac{x\sqrt{1-x^2}}{1-x}}$

The attached graph shows the equivalence of the polar and rectangular forms.

4 0

2 years ago

2x^2y^5 + 4xy^3 please answer

irina [24]

Answer:

its B, the 2xy3...thingy

8 0

3 years ago