0.6*10m=6m 0.6*5n=3n rewrite 6m-3n
hope this helps have a nice nite
Answer:
False
Step-by-step explanation:
Let p1 be the population proportion for the first population
and p2 be the population proportion for the second population
Then
p1 = p2
p1 ≠ p2
Test statistic can be found usin the equation:
where
- p1 is the sample population proportion for the first population
- p2 is the sample population proportion for the second population
- p is the pool proportion of p1 and p2
- n1 is the sample size of the first population
- n2 is the sample size of the second population.
As |p1-p2| gets smaller, the value of the <em>test statistic</em> gets smaller. Thus the probability of its being extreme gets smaller. This means its p-value gets higher.
As the<em> p-value</em> gets higher, the null hypothesis is less likely be rejected.
C=65
If its wrong I’m really sorry:(
Answer:
-30
Step-by-step explanation:
-|-30-(10-20)|-|5-(10-15)|=-|-30-(-10)|-|5-(-5)|
=-|-30+10|-|5+5|
=-|-20|-|10|
=-(20)-(10)
= -20-10
= -30