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bonufazy [111]
3 years ago
14

Will mark brainliest

Computers and Technology
1 answer:
Romashka [77]3 years ago
4 0

Answer:

1 a

2 d

3 c

4 a

Explanation:

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Consider the function definition void Demo( int& intVal, float floatVal ) { intVal = intVal * 2; floatVal = float(intVal) +
Fynjy0 [20]

Answer:

myInt=40

myFloat=4.8

Explanation:

First look at the function definition .It has two arguments intVal is passed by reference while floatVal is passed by value.So the changes done on the myInt variable will be reflected on the original argument because when a variable is passed by reference the the changes are reflected on the original argument but when a variable is passed by value the function created a duplicate copy of it and work on them so changes are not reflected on the original argument.So myInt will get doubled while myFloat will remain the same.

5 0
3 years ago
Jim is an experienced security professional who recently accepted a position in an organization that uses Check Point firewalls.
Contact [7]

Answer: D) CCSA

Explanation: THE CHECKPOINT CCSA(CERTIFIED SECURITY ADMINISTRATOR) is a computer based certification offered by different Computer Institutions in order to equip computer experts or systems engineers on the activities or process or knowledge needed to enhance the security domain of computer systems.

Check Point Firewall is a component of the Software Blade architecture which provides advanced firewall features like VPN and mobile device connectivity.

5 0
4 years ago
To assist a user, a help desk technician is able to take advantage of a Windows proprietary network protocol that allows the tec
puteri [66]

In order to assist an end user, a help desk technician can use the network protocol with a default TCP/IP port number of <u>3389</u>.

<h3>What is the TCP/IP protocol suite?</h3>

The TCP/IP protocol suite is an abbreviation for Transmission Control Protocol and Internet Protocol and it's a standard framework for the transmission (prepare and forward) of information on digital computers over the Internet.

In the Transmission Control Protocol and Internet Protocol (TCP/IP) suite, a help desk technician can use the network protocol with a default TCP/IP port number of <u>3389</u> to assist an end user by opening a graphical user interface to connect with the end user's Windows computer.

Read more on TCP here: brainly.com/question/17387945

#SPJ1

7 0
2 years ago
Consider a swapping system in which memory consists of the following hole sizes in memory order: 10 MB, 4 MB, 20 MB, 18 MB, 7 MB
lyudmila [28]

Answer:

a) 20 MB

b) 10 MB

c) 18 MB

Explanation:

First fit method works by keeping list of jobs which are ordered by memory location. This list of jobs contains free/busy status. Free means that hole is available and it takes the memory requests and busy is for the memory space is occupied.

In first fit method the first process takes the first available hole or memory with space greater than or equal to the size of the job. OS assigns process to nearest memory partition available with sufficient size.

For the request for 12 MB the hole with size 20 MB is taken as its nearest memory location of sufficient size than 10 and 4 MB. Now the status of this is busy as its taken by a job.

Next for the request of 10 MB the sufficient nearest memory hole is 10 MB as its equal to the size of the job. The status is changed to busy.

Next for the request of 9 MB the sufficient nearest hole is 18 MB as the 10 and 20 MB are already taken and 4 MB is not sufficient so the first sufficient available hole is of 18 MB.

5 0
4 years ago
The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea
ANTONII [103]

The mean of a sequence of numbers is the average.

The true statement is: \mathbf{mn = m_1n_1 + m_2n_2}

The given parameters are:

\mathbf{Mean=m}

\mathbf{Size=n}

The mean of a dataset is calculated as:

\mathbf{Mean = \frac{Sum}{Count}}

So, we have:

\mathbf{m = \frac{Sum}{n}}

Multiply both sides by m

\mathbf{Sum = mn}

When the sequence is split into two, we have:

\mathbf{\sum x_1 = m_1n_1}

\mathbf{\sum x_2 = m_2n_2}

Where:

\mathbf{Sum = \sum x_1 + \sum x_2}

So, we have:

\mathbf{mn = m_1n_1 + m_2n_2}

Hence, the true statement is: \mathbf{mn = m_1n_1 + m_2n_2}

Read more about mean and averages at:

brainly.com/question/25421763

5 0
3 years ago
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