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miskamm [114]
3 years ago
13

Rank these three account types in order of decreasing liquidity. Start by picking the most liquid account type first

Computers and Technology
2 answers:
Ghella [55]3 years ago
5 0
As there are no options given, I will simply mention the three most liquid accounts in order:

<span>1. Checking Account
2. Savings Account
3. Money Market Deposit Account

Account liquidity refers to the ease and comfort with which you can take your money out of an account from a bank, there are various bank accounts which can be referred to as liquid assets.</span>
uysha [10]3 years ago
4 0

wrong answer the correct order is


checking

certificate of deposit

savings

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kupik [55]

Answer:

Protection for your business and Increased productivity

Explanation:

This is because it ensures your employees aren't at risk from potential threats and, since there no virus, the computers will work well (not slow down)

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How could your program be useful in the real world?
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Answer:

to answer the question I need to know what your program is and what it does

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3 years ago
Write a C++ program to calculate the course score of CSC 126. 1. A student can enter scores of 3 quizzes, 2 exams, and a final e
miss Akunina [59]

Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

   double quiz1, quiz2, quiz3, exam1, exam2, finalexam,quiz;

   cout<<"Quiz 1: "; cin>>quiz1;

   cout<<"Quiz 2: "; cin>>quiz2;

   cout<<"Quiz 3: "; cin>>quiz3;

   cout<<"Exam 1: "; cin>>exam1;

   cout<<"Exam 2: "; cin>>exam2;

   cout<<"Final Exam: "; cin>>finalexam;

   if(quiz1<=quiz2 && quiz1 <= quiz3){        quiz=(quiz2+quiz3)/2;    }

   else if(quiz2<=quiz1 && quiz2 <= quiz3){        quiz=(quiz1+quiz3)/2;    }

   else{         quiz=(quiz1+quiz2)/2;     }

   int weight = 0.20 * quiz + 0.30 * ((exam1 + exam2)/2) + 0.50 * finalexam;

   cout<<"Average Weight: "<<weight<<endl;

   if(weight>=91 && weight<=100){        cout<<"Letter Grade: A";    }

   else if(weight>=81 && weight<=90){        cout<<"Letter Grade: B";    }

   else if(weight>=70 && weight<=80){        cout<<"Letter Grade: C";    }

   else{        cout<<"Letter Grade: F";    }

   return 0;

}

Explanation:

See attachment for complete program where comments were used to explain difficult lines

Download cpp
8 0
3 years ago
Write a program that asks the user to enter a date in MM/DD/YYYY format that is typical for the US, the Philippines, Palau, Cana
stepladder [879]

Answer:

In Python:

txt = input("Date in MM/DD/YYYY format: ")

x = txt.split("/")

date=x[1]+"."

if(int(x[1])<10):

   if not(x[1][0]=="0"):

       date="0"+x[1]+"."

   else:

       date=x[1]+"."

   

if(int(x[0])<10):

   if not(x[0][0]=="0"):

       date+="0"+x[0]+"."+x[2]

   else:

       date+=x[0]+"."+x[2]

else:

   date+=x[0]+"."+x[2]

   

print(date)

Explanation:

From the question, we understand that the input is in MM/DD/YYYY format and the output is in DD/MM/YYYY format/

The program explanation is as follows:

This prompts the user for date in MM/DD/YYYY format

txt = input("Date in MM/DD/YYYY format: ")

This splits the texts into units (MM, DD and YYYY)

x = txt.split("/")

This calculates the DD of the output

date=x[1]+"."

This checks if the DD is less than 10 (i..e 1 or 01 to 9 or 09)

if(int(x[1])<10):

If true, this checks if the first digit of DD is not 0.

   if not(x[1][0]=="0"):

If true, the prefix 0 is added to DD

       date="0"+x[1]+"."

   else:

If otherwise, no 0 is added to DD

       date=x[1]+"."

   

This checks if the MM is less than 10 (i..e 1 or 01 to 9 or 09)

if(int(x[0])<10):

If true, this checks if the first digit of MM is not 0.

   if not(x[0][0]=="0"):

If true, the prefix 0 is added to MM and the full date is generated

       date+="0"+x[0]+"."+x[2]

   else:

If otherwise, no 0 is added to MM and the full date is generated

       date+=x[0]+"."+x[2]

else:

If MM is greater than 10, no operation is carried out before the date is generated

   date+=x[0]+"."+x[2]

This prints the new date

print(date)

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3 years ago
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otez555 [7]

Answer:

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6 0
4 years ago
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