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Alina [70]
3 years ago
7

Pls Solve my question ​

Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0

hope this will help you more

You might be interested in
The lengths of the sides of an equilateral triangle are 3(x + )cm, (5x +2y-1) cm and 5x +1 Cm Find the side length of the triang
pochemuha

Answer:

Correct option is A

Since it is an equilateral triangle, the lengths of the sides are equal

So, x+3 y=3 x+2 y−2=4 x+

2

1

​

y+1

x+3 y=3 x+2 y−2

y=2 x−2

2 x−y=2 ...(1)

Also, 4 x+

2

1

y+1=x+3 y

8 x+y+2=2 x+6 y

6 x+2=5 y

6 x−5 y=−2   ...(2)

Multiplying e q(1) by  5 we get,

10 x−5 y=10      ...(3)

Subtracting e q(2) from e q(3) we get,

4 x=12⇒x=3

y=2 x−2=4

The length of one side of equilateral triangle = x+3 y =3+3(4)=15 units

5 0
3 years ago
HELP please im doing a test and it's due in 7 minutes
Reil [10]

Answer:

2.62*10^5

can you also please mark me as brainliest?

5 0
3 years ago
Gabriel has $2 worth of nickels and dimes. He has 2 more dimes than
Zinaida [17]

Answer:

12 Nickles

6 dimes

Step-by-step explanation:

yeah bro i think thats the answe

3 0
1 year ago
At a local sandwich shop the average customer spends $25 at dinner with a standard deviation of $2.30. In a simple random sample
oee [108]

Answer:

The probability that the mean receipt for dinner is between $24.50 and $25.50 is

P(24.50≤ x ≤ 25.50)= 0.8324

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given mean of Population(μ) = $25

Given standard deviation of the Population  (σ) = 2.30

Sample size 'n' = 40

Let 'X' be the random variable in normal distribution

Given X₁ = 24.50

Z_{1} =\frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{24.50-25}{\frac{2.30}{\sqrt{40} } } = -1.375

Given X₂ = 25.50

Z_{2} =\frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{25.50-25}{\frac{2.30}{\sqrt{40} } } = 1.3751

<u><em>Step(ii):-</em></u>

The probability that the mean receipt for dinner is between $24.50 and $25.50

P(x₁≤ x ≤ x₂) = P(Z₁≤ z ≤ Z₂) = A(Z₂) + A(z₁)

P(24.50≤ x ≤ 25.50) = P(-1.375≤ z ≤ 1.375) = A(1.375) + A(1.375)

P(24.50≤ x ≤ 25.50)= 2 A( 1.375)

                               = 2 × 0.4162 ( from normal table)

                              = 0.8324

<u><em>Final answe</em></u>r:-

The probability that the mean receipt for dinner is between $24.50 and $25.50 is 0.8324

4 0
3 years ago
Alegbra 2: pls help!!
siniylev [52]

Answer:

Sean's rocket lands 3 seconds after Kiara's rocket.

Step-by-step explanation:

Kiara:  f(t)= -16t² + 80t

Sean:  h(t) = -16t² + 120t + 64

Assume that both rockets launch at the same time.  We need to be suspicious of Sean's rocket launch.  His equation for height has "+64" at the end, whereas Kiara's has no such term.  The +64 is the starting height iof Sean's rocket.  So Kiara has a 64 foot disadvantage from the start.  But if it is a race to the ground, then the 64 feet may be a disadvantage.  [Turn the rocket upside down, in that case.  :) ]

We want the time, t, at which f(t) and h(t) are both equal to 0 (ground).  So we can set both equation to 0 and calculate t:

Kiara:  f(t)= -16t² + 80t

0 = -16t² + 80t

Use the quadratic equation or solve by factoring.  I'll factor:

0 = -16t(t - 5)

T can either be 0 or 5

We'll choose 5.  Kiara's rocket lands in 5 seconds.

Sean:  h(t) = -16t² + 120t + 64

0= -16t² + 120t + 64

We can also factor this equation (or solve with the quadratic equation):

0 = -8(t-8)(2t+1)

T can be 8 or -(1/2) seconds. We'll use 8 seconds.  Sean's rocket lands in 8 seconds.

Sean's rocket lands 3 seconds after Kiara's rocket.

8 0
2 years ago
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