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I am Lyosha [343]
3 years ago
5

You are implementing a RAID storage system and have found a system with eight 100 GB drives. How much storage space will you hav

e available? How does the OS handle this RAID?
Computers and Technology
1 answer:
asambeis [7]3 years ago
4 0

Answer:

The space available will vary between 800 GB (100%) and 400 GB (50%) of the total disks, depending on the RAID level.

The OS will handle the RAID as a single disk.

Explanation:

Each RAID level implements parity and redundancy in a different way, so the amount of disks used for this extra information will reduce the space available for actual storage.

Usual RAID levels are:

<u>RAID 0:</u> does not implement any redundancy or parity, so you will have available 100% of the total storage: 8 x 100 GB = 800 GB

<u>RAID 1:</u> Duplicates all the information in one disk to a second disk. Space is reduced in half: 400 GB

<u>RAID 5:</u> Uses the equivalent of 1 disk of parity data distributed evenly on each disk, meaning the space available is \frac{n-1}{n} of the total disks: \frac{7}{8} of 800 GB = 700 GB

Writting and reading the information on a RAID storage is handled by a raid controller, either implemented in hardware or software. The OS will "see" a single disk and will read or write information as usual.

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You have a host device with an assigned IP address of 192.168.15.100 and a subnet mask of 255.255.255.192. To what network does
aalyn [17]

The options are missing from the question.

Below are the options.

A) 192.168.15.0

B) 192.168.15.16

C) 192.168.15.32

D) 192.168.15.64

Answer: The correct option to the question is option D

192.168.15.64

Explanation:

The Network is: 192.168.15.64/26 11000000.10101000.00001111.01000000

Then the Broadcast is: 192.168.15.127 11000000.10101000.00001111.01111111

We see the HostMin as: 192.168.15.65 11000000.10101000.00001111.01000001

And the HostMax as: 192.168.15.126 11000000.10101000.00001111.01111110

3 0
2 years ago
Write pseudo code that performs the following: Ask a user to enter a number. If the
CaHeK987 [17]
Answer:
BEGIN
INPUT N
IF N>0 AND N<10 THEN
OUTPUT "blue"
ELSE
IF N>10 AND N<20 THEN
OUTPUT "red"
ELSE
IF N>20 AND N<30 THEN
OUTPUT "green"
ELSE
OUTPUT "It is not a correct color option"
ENDIF
END.

Explanation:

3 0
1 year ago
What does c++ programming mean?
cestrela7 [59]

Answer:

It's an internal joke to say the language is basically C with some extra stuff (like classes)

the "++" is short for

C += 1 or

C = C + 1 which is a common calculation among programmers so they named it C++ to be a more commercial and attractive name than "C with classes"

Explanation:

8 0
2 years ago
Which of the following solutions enables simultaneous digital transmission of voice, video, data, and other network services ove
Annette [7]

Answer:

3. ISDN

Explanation:

ISDN ( Integrated Services Digital Network  ) -

It is the used for the simultaneous digital transmission of network service , data , video and voice , instead of the old circuits of the public switched telephone network ( PSTN ) , is referred to as ISDN .

The characteristic feature of ISDN is that it integrates the data and speech on the same lines , which is not possible in PSTN .

Hence, from the given information of the question,

The correct option is ISDN .

8 0
2 years ago
2. Write a simple program in C++ to investigate the safety of its enumeration types. Include at least 10 different operations on
erastovalidia [21]

Answer:

Check the explanation

Explanation:

To solve the question above, we will be doing some arithmetic and bit wise operations on enum values. in addition to that, we are asserting the array with INTCOUNT  and also printing the size of array i.e 12 and we are adding BIG_COUNT enum value to 5 and the result is 25.

#include<stdio.h>

enum EnumBits

{

ONE = 1,

TWO = 2,

FOUR = 4,

EIGHT = 8

};

enum Randoms

{

BIG_COUNT = 20,

INTCOUNT = 3

};

int main()

{

// Basic Mathimatical operations

printf("%d\n",(ONE + TWO)); //addition

printf("%d\n",(FOUR - TWO)); //subtraction

printf("%d\n",(TWO * EIGHT)); //multiplication

printf("%d\n",(EIGHT / TWO)); //division

// Some bitwise operations

printf("%d\n",(ONE | TWO)); //bitwise OR

printf("%d\n",(TWO & FOUR)); //bitwise AND

printf("%d\n",(TWO ^ EIGHT)); //bitwise XOR

printf("%d\n",(EIGHT << 1)); //left shift operator

printf("%d\n",(EIGHT >> 1)); //right shift operator

// Initialize an array based upon an enum value

int intArray[INTCOUNT]; // declaring array

// Have a value initialized be initialized to a static value plus

int someVal = 5 + BIG_COUNT; //adding constant and BIG_COUNT variable

printf("%d\n",someVal); //value will be 25

printf("%d",sizeof(intArray)); //value will be 12

return 0;

}

Kindly check the attached image below for the Code and Output Screenshots:

6 0
2 years ago
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