Answer:
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Step-by-step explanation:
Answer:
21
Step-by-step explanation:
3+(a+4)(8-b)
3+(5+4)(8-6)
3+(9)(2)
3+18
21
Answer:
Step-by-step explanation:
We assume your equations are intended to be ...

Then the profit equation is ...

The partial derivatives of profit with respect to x and y are zero when profit is maximized.
∂P/∂x = 0 = -2x +2y +2
∂P/∂y = 0 = 2x -18y +94
Simplifying, these equations are ...
Substituting the first into the second gives ...
x -9(x -1) = -47
-8x = -56
x = 7
y = 7 -1 = 6
The company will maximize profit by selling 7000 panels of type A and 6000 panels of type B.
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
v=6
Step-by-step explanation:
2v is positive so keep it
then 2v=12
v=6