Answer:
59.15 in^2
Step-by-step explanation:
Using Heron's formula
semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4
Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2
Alright, so the distance formula is sqrt((x1-x2)^2+(y1-y2)^2), and plugging that in, we get sqrt((0-3)^2+(3-10)^2)=sqrt((-3)^2+(-7)^2)=sqrt(9+49)=sqrt(58)=around 7.6
Answer:
Step-by-step explanation:
