The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
when we see the geometry sum my headache is started
Perpendicular lines will meet at a 90 degree angle (a right angle)...so ur answer is B
Make a few rough drafts then find a peer to check over it
9514 1404 393
Answer:
u = -3 3/7
Step-by-step explanation:
The new value of v is 4/-7 = -4/7 of the old value. Because u varies directly, its new value will also be -4/7 of the old value.
u = -4/7(6) = -24/7
u = -3 3/7
