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Sloan [31]
3 years ago
13

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Mathematics
2 answers:
vodomira [7]3 years ago
7 0

Finding the discriminate of a quadratic formula determines the number and type of answers.

The formula is b^2 -4(ac)

a = 6. b = -7 and c = -4

-7^2 -4(6*-4) = 145

The answer is a positive number so this means there are 2 real solutions.

stepladder [879]3 years ago
4 0

Answer:

two real solutions

Step-by-step explanation:

We can use the discriminant to determine the type and number of solutions

b^2 -4ac  where ax^2 +bx +c

If b^2 -4ac > 0 we have 2 real solutions

b^2 -4ac = 0 there is 1 real solution

b^2 -4ac < 0 there are 2 complex solutions

6x^2 -7x -4 = 0

a=6  b =-7  c = -4

b^2 -4ac

(-7)^2 -4(6)(-4)

49 + 96

145>0

There are real solutions

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X+y=5<br> x×y=6<br> Solve simultaneously with steps
igor_vitrenko [27]

Answer:

(3, 2), (2, 3)

Step-by-step explanation:

x + y = 5

xy = 6

Solve the first equation for x.

x = 5 - y

Substitute 5 - y for x in the second equation.

xy = 6

(5 - y)y = 6

5y - y² = 6

y² - 5y + 6 = 0

Factor.

(y - 2)(y - 3) = 0

y - 2 = 0  or y - 3 = 0

y = 2  or y = 3

Now substitute 2 for y in the first equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

One solution is x = 3; y = 2, or (3, 2).

Now substitute 3 for y in the first equation and solve for x.

x + y = 5

x + 3 = 5

x = 2

Another solution is x = 2; y = 3, or (3, 2).

Answer: (3, 2), (2, 3)

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