Each solid is composed of a rectangular prism and a regular prism. Find the surface area of the solid.

If f(x)= -3x-5 and g(x)= 4x-2 find (f+g)(x)

juin [17]

Known :

f(x) = -3x - 5

g(x) = 4x - 2

Asked :

(f+g)(x) = ...?

Answer :

(f+g)(x) = (-3x - 5) + (4x - 2)

= (-3x + 4x) + (-5 - 2)

= x + (-7)

= x - 7

So, the value of (f+g)(x) is x - 7

Hope it helpful and useful :)

5 0

2 years ago

Read 2 more answers

Please help Q 4 the order pairs

Novosadov [1.4K]

Plug in each of the answer choices into the 'y=' button and check each table. If all of the ordered pairs are shown in one equation table, then that is your representing function.

4 0

2 years ago

Find the derivative of the function at P 0 in the direction of A. f(x,y,z) = 3 e^x cos(yz), P0 (0, 0, 0), A = - i + 2 j + 3k

Alik [6]

The derivative of $f(x,y,z)$ at a point $p_0=(x_0,y_0,z_0)$ in the direction of a vector $\vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k$ is

$\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}$

We have

$f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k$

and

$\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}$

Then the derivative at $p_0$ in the direction of $\vec a$ is

$3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}$

3 0

3 years ago

Urgent! Two questions! (Pre Calc) (30 points)

mina [271]

Problem One
Sin(90 + q) = sin(90)*cos(q) + sin(q)*cos(90)
sin(90 + q) = 1 * cos(q) + sin(q)*0
sin(90 + q) = cos(q)

You can elimate anything beginning with Cos
You can also eliminate the sin function with a minus between it.

Problem 2
Sin(x) = 1/csc(x) That makes C and D incorrect.
Correct answer has to be A. Since this is a multiple choice question you can't qualify the answer, but there are some points that exhibit questionable behavior, like 2 $\pi$ *f*t = 0 for example. The function becomes undefined.

4 0

2 years ago

4 hours 30 minutes = ? Minutes

tigry1 [53]

The answer is: " 270 minutes " .
__________________________________________________________
→ There are "270 minutes" in "4 hours and 30 minutes" .
__________________________________________________________
Explanation:
__________________________________________________________
Method 1):
__________________________________________________________
Note: 60 minutes = 1 hour (exactly);

30 minutes = ? hr ? ;

→ (30 minutes) * (1 hr/ 60 minutes) ;

= (30/60) hr = (3/6) hr = (3÷3)/(6÷3) hr ;

= " $\frac{1}{2}$ hr " ;

or; write as: " 0.5 hr " .
_________________________________________________________

So "4 hours & 30 minutes" = 4 hours + 0.5 hours = 4.5 hours.

→ 4.5 hours = ? minutes ;

The answer is: " 270 minutes" . 4.5 hours * $\frac{60 min}{1 hr}$ ;

= (4.5 * 60) minutes = " 270 minutes " .

→ The answer is: " 270 minutes ".
___________________________________________________________
Method 2)
___________________________________________________________

"4 hours and 30 minutes" =  ?  minutes " .
___________________________________________________________

→ " 4 hours =  ?  minutes " ;

→ 4 hr . * $\frac{60 min}{1 hr}$ = (4 * 60) minutes = 240 min. ;

→ There are " 240 minutes in 4 hours" .

→ To find the number of "minutes" in "4 hours and 30 minutes" ;

→ we takes the number of minutes in 4 hours—which is "240 minutes"—and add "30 minutes" to that number; as follows:

→ " 240 minutes + 30 minutes " ;

to get: " 270 minutes " .
_______________________________________________________

 → There are "270 minutes" in "4 hours and 30 minutes" .
_______________________________________________________

The answer is: " 270 minutes " .
_______________________________________________________

4 0

2 years ago