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Mademuasel [1]
3 years ago
5

Find the missing side pls ​

Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:

I would say 21.5 but if I'm wrong don't be mad I'm legit trash at math

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What are the missing reasons in the proof abcd with diagonal bd prove abd = cdb
Marta_Voda [28]
3) Definition of a parallelogram
4) Alternate interior angles
5) Reflexive property
6) ASA property
Please say if I got anything wrong!
8 0
2 years ago
Read 2 more answers
What is the value of (j+3k)(5)?<br><br> j(x) = (x + 4)^2; k(x) = 8 - x<br><br> (j + 3k)(5) =
jeyben [28]

Step-by-step explanation:

J=(x+4)²

K=(8-x)

X=5

=J+3k

=(x+4)(x+4)+3(8-x)

=(x²+8x+16+24-3x)

=25+25+40

=90

Alternatively:

J=(5+4)²

J=81

K=8-5

K=3

J+3k

81+3(3)

81+9

90

3 0
3 years ago
In a certain chemical the ratio of zinc to copper is 4 to 15. A jar of the chemical contains 345 of copper how many grams of zin
vekshin1

Answer:

92.

Step-by-step explanation:

By proportion the mass of zinc = (345/ 15) * 4

= 92.

7 0
2 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
2 years ago
Just Checking
Luda [366]
The answer is b because 95 confidence is interval for the mean lifespan
7 0
3 years ago
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