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Alina [70]
3 years ago
10

(9 x 10) + (4 x 0.1) how is this temperature in degrees fahrenheit written as a numeral?

Mathematics
2 answers:
lana [24]3 years ago
8 0

Answer:

the answer is 90×4= 360°F

mash [69]3 years ago
3 0

Answer:

360°F

Step-by-step explanation:

When you multiply the numerals in the brackets . The first set of brackets is 90 then the second is 4.0 then multiply them and you will get 360.0°F

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Alex73 [517]
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3 years ago
Mr. Lance designed a class banner shaped like the polygon shown. What is the name of the polygon
dedylja [7]
The Polygon has 5 sides hence it is called a Pentagon.

Note : if it is 4 sided, it could be a square, or rectangle or parallelogram or rhombus.

5 sided is a Pentagon

6 sided is an Hexagon

7 sided is a Heptagon

8 sided is an Octagon

9 sided is a  Nonagon

10 sided is a Decagon

The one in the question is 5 sided, so it is a Pentagon.
5 0
3 years ago
A florist delivers flowers to anywhere in town. D is the distance from the delivery address to the florist shop in miles. The co
Inessa [10]

A. C (6) = 15.24; C 11 = 22.09.

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from the shop.

C (11) represents the cost, $22.09, of delivering flowers to a destination that is 11 miles

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b.

8 0
3 years ago
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The answer needs to be a mixed number a integer or a proper fraction.
kobusy [5.1K]

Answer:

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7 0
3 years ago
Indicate the equation of the given line in standard form. The line that is the perpendicular bisector of the segment whose endpo
noname [10]
Well the line that bisects RS, will cut RS in two equal halves, therefore, that line will cut RS perpendicularly at the midpoint of RS.

now, what the dickens is the midpoint of RS anyway?

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
R&({{ -1}}\quad ,&{{ 6}})\quad 
%  (c,d)
S&({{ 5}}\quad ,&{{ 5}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{5-1}{2}~~,~~\cfrac{5+6}{2} \right)\implies \stackrel{midpoint}{\left(2~~,~~\frac{11}{2}  \right)}

so, we know that perpendicular line, will have to go through (2, 11/2)

now, a perpendicular line to RS, will have a negative reciprocal slope to it.  Well, what is the slope of RS anyway?

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ -1}}\quad ,&{{ 6}})\quad 
%   (c,d)
&({{ 5}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-6}{5-(-1)}\implies \cfrac{5-6}{5+1}\implies -\cfrac{1}{6}

and let's check the reciprocal negative of that,

\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{6}\\\\
slope=-\cfrac{1}{{{ 6}}}\qquad negative\implies  +\cfrac{1}{{{ 6}}}\qquad reciprocal\implies + \cfrac{{{ 6}}}{1}\implies 6

so, then, what's is the equation of a line whose slope is 6, and goes through 2, 11/2?

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 2}}\quad ,&{{ \frac{11}{2}}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\cfrac{11}{2}=6(x-2)
\\\\\\
y-\cfrac{11}{2}=6x-12\implies -6x+y=-12+\cfrac{11}{2}\implies \stackrel{\textit{standard form}}{-6x+y=-\cfrac{13}{2}}
6 0
3 years ago
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