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Hunter-Best [27]
3 years ago
13

In right triangle ABC with right angle C, the length of AB is 31 and the length of BC is 14. Find the measure of angle B. Round

to the nearest tenth.
35.6°

63.2°

24.3°

26.8°
Mathematics
1 answer:
aksik [14]3 years ago
6 0

Answer:

1. Sine

2. 14.1

3. Cosine

4. 63.2

5. 418

> Just took it, your welcome :)

Step-by-step explanation:

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Y= 4/5 x-7 what are the y and x intercepts?
solmaris [256]

The x intercept is (8.75, 0) and y - intercept is (0, -7)

<em><u>Solution:</u></em>

Given that we have to find the x and y intercepts

Given equation is:

y = \frac{4}{5}x - 7

The x intercept is the point where the line crosses the x axis

The y intercept is the point where the line crosses the y axis

<em><u>Finding x - intercept:</u></em>

To find the x-intercept of a given equation, plug in 0 for 'y' and solve for 'x'

Substitute y = 0 in given equation

0 = \frac{4}{5}x - 7\\\\\frac{4x}{5} = 7\\\\4x = 35\\\\x = \frac{35}{4} = 8.75

Thus x intercept is (8.75, 0)

<em><u>Finding y - intercept:</u></em>

To find the y-intercept, plug 0 in for 'x' and solve for 'y'

Substitute x = 0 in given equation

y = \frac{4}{5} \times 0 - 7\\\\y = 0 - 7\\\\y = -7

Thus y - intercept is (0, -7)

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Vesnalui [34]

Answer:

width is 4

height is 20

Step-by-step explanation:

Area=½ width × height

let the width be x

height will be 6x - 4

40 = ½ × x × (6x - 4)

40 = 2/2 × 3x² - 2x

40 = 3x² - 2x

3x² - 2x - 40 = 0

3x² -12x + 10x - 40 = 0

3x(x-4) + 10(x-4) = 0

(3x + 10)(x - 4) = 0

x = -10/3 or 4

dimension cannot be negative

x is 4

6x-4= 6(4) - 4

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Show tan (x) + cot (x) • sec(x)
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\tan x+\cot x=\csc x.\sec x

Let us change tan x and cot x to sin x and cos x

\begin{gathered} \because\tan x=\frac{\sin x}{\cos x} \\ \because\cot x=\frac{\cos x}{\sin x} \end{gathered}

Substitute them on the left side

LHS=\frac{\sin x}{\cos x}+\frac{\cos x}{\sin x}=\frac{\sin^2x+cox^2x}{\cos x\sin x}

I multiplied the denominators and multiply each numerator by the opposite denominator

\because\sin ^2x+cox^2x=1\therefore L.H.S=\frac{1}{\sin x\cos x}

Now we will work on the right hand side

\begin{gathered} \because\csc x=\frac{1}{\sin x} \\ \because\sec x=\frac{1}{\cos x} \end{gathered}

Substitute them on the right side

\because R.H.S=\frac{1}{\sin x}\times\frac{1}{\cos x}=\frac{1}{\sin x\cos x}

The L.H.S = R.H.S = 1/(sin x cos x)

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Answer:

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Step-by-step explanation:

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