If there were actual numbers at the ends of the line,
you'd have no trouble inventing some new numbers
that fit in the space between them.
OK. Put actual numbers at the ends !
Pick up your calculator, and find the numbers for √56 and √58 .
You don't need them to be exact ... just keep a few decimal places.
√56 = 7.483...
√58 = 7.615...
There you are. Now you have actual numbers at the ends
of that piece of number line in the question. Now, can you
make up numbers that fit between them ?
Here are a few that I invented:
7.484
7.485
7.486
7.599
7.600
7.614
You should make your own.
Don't worry about running out of numbers ...
there are an infinite number of them.
D/c = 6/7 => d = 6c/7
d + c = 52
6c/7 + c = 52
6c + 7c = 364
13c = 364
c = 364÷13
c = 28
d = 52 - 28
d = 24
(2.2x10^-1)=22x10^-2
(22x10^-2)+(2.3x10^-2) = 24.3x10^-2
=2.43x10^-1
Therefore, the answer is D
Answer:
The Sample Size Need To be at least 114
Step-by-step explanation:
According to the Question,
- Given, A university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standard deviation from a previous study is 6.2 hours.
The Maximum Error(E) is given as 1.5 hours and the standard deviation(σ) is 6.2 hours.
- Now, For 99% Confident the level of value α is 0.01.
α/2 = 0.01/2 ⇒ 0.005
- Thus, From The table, We get that the value of
is 2.58.
Hence, the sample size n can be found as
n = {
}²
n = {2.58 × 6.2}² / 1.5²
n = 113.72 .
So, The Sample Size Need To be at least 114.
