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puteri [66]
3 years ago
14

PLEASE HELP! Solve for q(x) and r(x). (4x^3-3x^2+5x-7)/(x-2) = q(x)+ r(x)/(x-2)

Mathematics
1 answer:
Lerok [7]3 years ago
7 0
Asked and answered elsewhere.
brainly.com/question/9169487
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Solve the system algebraically. Check your work.
Luden [163]

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10     (1)

And 3x+2y=63x+2y=6      (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30      (3)

15x+10y=3015x+10y=30      (4)

Now subtract  (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

8 0
3 years ago
Please help out need it​
juin [17]

Answer:

at the answer is about 5.29

Step-by-step explanation:

to do this u need the pythagorean theorem.

a squared+ b squared=c squared

we have the a and c values so what u would do is c squared- a squared. (8 squared - 6 squared = b squared.

8 0
3 years ago
Read 2 more answers
I need the awnser ASAP plz!!​
Ganezh [65]

Answer:

it is D

Step-by-step explanation:

the ratio is 1.5 so multiply 15 by 1.5

3 0
3 years ago
Solve the equation cot 2x + cot x =3
rusak2 [61]

tan2x*cotx - 3 = 0

We know that: tan2x = sin2x/cos2x and cotx = cosx/sinx

==> sin2x/cos2x *cosx/sinx = 3

Now we know that sin2x = 2sinx*cosx

==> 2sinxcosx/cos2x * cosx/sinx = 3

Reduce sinx:

==> 2cos^2 x/ cos2x = 3

Now we know that cos2x = 2cos^2 x-1

==> 2cos^2 x/(2cos^2 x -1) = 3

==> 2cos^2 x = 3(2cos^2 x -1)

==> 2cos^2 x = 6cos^2 x - 3

==> -4cos^2 x= -3

==> 4cos^2 x = 3

==> cos^2 x = 3/4

==> cosx = +-sqrt3/ 2

<span>==> x = pi/6, 5pi/6, 7pi/6, and 11pi/6</span>

3 0
3 years ago
How many inches are in 3.5 yards?
Leno4ka [110]
126 inches (Ask me if you have any questions :) )
5 0
3 years ago
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