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mariarad [96]
2 years ago
12

Need help Identify the domain of the function shown in the graph

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
8 0

Answer:

B

Step-by-step explanation:

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Show that the triangle below is not a right-angled triangle.
Paha777 [63]

Step-by-step explanation:

A right triangle is a triangle in which one of the angles is a 90∘ angle.

(5x - 8)  + (2x - 5)  + (2x  + 3) = 180 \\ 9x - 10 = 180 \\ 9x = 190 \\ x =  \frac{190}{9}  \\ x = 21.11

(5x - 8) =97.56  \\ (2x - 5)  =37.22  \\ (2x + 3) =45.22  \\

Since None of the angels is 90° , so the triangle is not a right triangle.

7 0
3 years ago
If a < 0 and c > b, circle the expression that is greater:
matrenka [14]

Answer:

The expression that is greater is a (b - c)

Step-by-step explanation:

  • a < 0 and c > b, this means <u>(by the addition property)</u> that c - c > b - c⇒0 > b - c

so for the product <u>a(b - c) </u>we would have a multiplication of a negative number <em>a</em> and another negative number <em>(b - c)</em>. We know that the result of the <u>multiplication of two negative numbers  is a positive number.</u>

Therefore, a (b - c) > 0

  • a < 0 and c > b, this means <u>by the addition property</u> that c - b > b - b⇒ c - b > 0

so for <u>a(c - b)</u>, we have the negative number <em>a</em> multiplied by the positive number <em>(c - b). </em>We know that the result of the <u>multiplication of a negative number by a positive number is negative. </u>

<u>Therefore  a (c - b) < 0</u>

Thus, the expression that is greater is the positive one which is a (b - c)

5 0
3 years ago
Suppose the equation ax^2+bx+c=0 has no real solution and a graph of the related function has a vertex that lies in the second q
Veseljchak [2.6K]
If it has no real solutions, that means the graph does not intersect the x axis

since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up

so 'a' must be positive



if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
7 0
3 years ago
Tony can cycle a distance of 9 5/6 miles in 3/5 hours. What is his unit rate
Eva8 [605]

Answer:

95/6

3/5

Step-by-step explanation:

3 0
2 years ago
How do I solve this equation
Anestetic [448]
-x - y = 8
2x - y = -1

Ok, we are going to solve this in 2 parts.  First we have to solve for one of the variables in one of the equation in terms of the other variable.  I like to take the easiest equation first and try to avoid fractions, so let's use the first equation and solve for x.

-x - y = 8      add y to each side
-x = 8 + y      divide by -1
x = -8 - y

So now we have a value for x in terms of y that we can use to substitute into the other equation.  In the other equation we are going to put -8 - y in place of the x.

2x - y = -1
2(-8 - y) - y = -1      multiply the 2 through the parentheses
-16 - 2y - y = -1      combine like terms
-16 - 3y = -1            add 16 to both sides
-3y = 15                   divide each side by -3
y = -5

Now we have a value for y.  We need to plug it into either of the original equations then solve for x.  I usually choose the most simple equation.

-x - y = 8
-x - (-5) = 8            multiply -1 through the parentheses
-x + 5 = 8                subtract 5 from each side
-x = 3                      divide each side by -1
x = -3

So our solution set is

(-3, -5)

That is the point on the grid where the 2 equations are equal, so that is the place where they intersect.

4 0
3 years ago
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