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bija089 [108]
3 years ago
8

10 divided (-5)x-2x-8

Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer: -4x -8

See picture below for step by step

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Digiron [165]
The answer is g. 47.1

you use the formula
c= π d
then plug is 15 for d and you should get the answer
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What inequality is on the number line?​
Elis [28]
Answer:
y ≥ -5

Explanation:
y is greater than -5 because the darkened line is heading towards the positive side.
(The positives are greater than the negatives.)
(The smaller negative numbers are greater than the larger negative numbers.)
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Eva Maria borrowed money from her father and agreed to pay him 4% simple annual interest. At the end of 7 years, Eva Maria owes
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4% simple interest after 7 years is 28% interest.

$1736 interest is 28% of $6,200

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3 years ago
Read 2 more answers
Find the slope of the line that goes through (1, 3) and (-2,-6).
monitta

Answer:

m= -3

Step-by-step explanation:

slope intercept formula

(y2-y1)/ (x2-x1)

-6-3= -9

-2-1=-3

-9/3 =-3

3 0
4 years ago
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

3 0
3 years ago
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