If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
A
Step-by-step explanation:
5:9 is the original ratio.
we know that anything times 5 would have the ones place of either 5 or 0 so we can eliminate c and d. Then we test out the other two choices.
25/5=5
45/9=5
A is correct.
15/5=3
45/9=5
Option B is incorrect.
so, the ratio is 25:45
The answer is A!
Answer: The cost of each game is $2.50
Step-by-step explanation:
Let's find the equations for each friend:
Friend 1:
Pays $3 for the shoes, and plays 3 games, then if X is the cost of each game, Friend 1 pays a total of:
$3 + 3*X
Friend 2:
This friend buys a soda for $0.50, and he plays 4 games, remember that the cost of each game was X. then this friend pays:
$0.50 + 4*X
And we know that both friends pay the exact same amount, then we can write:
$3 + 3*X = $0.50 + 4*X
And solve this for X.
We need to isolate X, then we can move all the terms with X to the right, and all the terms without X to the left:
$3 - $0.50 = 4*X - 3*X
$2.50 = (4 - 3)*X = X
This means the cost of each game is $2.50
Answer:
363
Step-by-step explanation:
Formula for area of a circle
A = πr^2
Where r = radius
The circle has a given radius of 11
To find the area of the circle we simply substitute r in the formula with the value of the radius (11)
( Also note that the question says to use 3 for π )
A = πr^2
π = 3
r = 11
Substitute values in formula
A = (3)(11)^2
11^2 = 121
A = 121(3)
121(3) = 363
A = 363
