Complete question :
a ladder 5 meters long is leaning against a wall. the base of the ladder is sliding away from the wall at a rate of 1 meter per second. how fast is the top of the ladder sliding down the wall at the instant when the base is 4 meters from the wall?
Answer:
-4/3 m/s
Step-by-step explanation:
Using Pythagoras :
a² = x² + c²
5² = x² + y² - - - (1)
The horizontal distance x with respect to time t = 1m/sec
dx/dt = 1m/sec
To obtain the vertical height 'y' with respect to time t when x = 4
5² = x² + y²
Wen x = 4
5² = 4² + y²
25 = 16 + y²
y =√(25 - 16)
y = 3
Differentiate (1) with respect to t
x² + y² = 25 - ---- - (1)
2x * dx /dt + 2y dy/dt = 0
dx/dt = 1
x = 4.
y = 3
2(4)(1) + 2(3) * dy/dt = 0
8 + 6dy/dt = 0
6 dy/dt = - 8
dy/dt = - 8/6
dy/dt = - 4/3
The volume is 414,720 in³, which equals 240 ft³.
We need all of the units to be the same. Since 2 of the 3 measurements are in inches, we will convert the feet to inches. 12 inches = 1 foot, so
22.5(12) = 270
To find the volume of a rectangular prism (box), multiply the length, width, and height:
270(48)(32) = 414,720 in³
If we want this in cubic feet, we need to know first that 1 ft³ is a cube with side length 1 ft = 12 inches. This means that the volume is 12*12*12 = 1728 in³. Therefore there are 1728 in³ in 1 ft³:
414720/1728 = 240 ft³
The slope would be 1/1 or 1
I hope this helps!!!!!!!
Answer:
I notice that the second one is the same as the yellow part of the bar.
I wonder why is there an extra piece and it is green.
Step-by-step explanation:
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