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2 years ago

HELP ME PLEASE GUYS!! :)

Mathematics

2 answers:

baherus [9]2 years ago

8 0

If two lines intersect, then there is only one solution - where they cross.

Looking at the graph, we can see the intersection point of these two lines.

The intersection point is (1,1) - one unit to the right of the origin and one unit up.

Hope this helps! :)

Brrunno [24]2 years ago

4 0

Answer:

(2, 2)

Step-by-step explanation:

srry

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Please help asap :( "This is My final Grade " My Teacher wants a full explanation included with the answer .) please view the at

STALIN [3.7K]

Answer:

Step-by-step explanation:

circle A is

x²+y²+6x-4y-12=0

x²+6x +y²-4y =12

think (a+b)² = a²+2ab+b² we have a=x, b= 3

and (a-b)² = a²-2ab+b² so we have a=y, b=2

x²+6x +9 +y²-4y+4 = 12-9-4

(x+3)² +(y-2)²= -1

compare to the general equation of a circle (x-h)²+(y-k)² =r²

the center is at (-3,2) and the radius is √-1 =i

Circle B has center (0, -4) and radius 3 so the equation is

(x-0)²+(y-(-4))² =3²

x² +(y+4)² = 9

point (√8, -3) is on the circle if it verifies the equation

√8² +(-3+4)² = 9

8+1 =9 true so the point is on the circle

Circle A and circle B are not similar because they do not have the same center and radius

4 0

2 years ago

You are considering developing a regression equation relating a dependent variable to two independent variables. One of the vari

lys-0071 [83]

Answer:

Step-by-step explanation:

a. How many dummy variables are needed to represent the categorical variable?

We need 1 less dummy variable than outcomes for the categorical variable.

categorical variable has 2 outcomes

So, we need 2-1 = 1 dummy variable.

Answer: 1

Note: If our categorical variable had 5 outcomes, we would need 5-1 = 4 dummy variables.

b. Write the multiple regression equation relating the dependent variable to the independent variables.

Note: Depending your your professor, this can be written one of the following ways...

yhat = a + b1 x1 + bx2

yhat = b0 + b1 x1 + b2 x2

yhat = beta0hat + beta1hat x1 + betahat2 x2

where x1 is the ratio variable

and x2 is the dummy variable

c. Interpret the meaning of the coefficients in the regression equation.

b0 = the predicted value of y when x1 and x2 both equal 0.

b1 = the change in y when x1 increases by 1 unit holding x2 constant.

b2 = the predicted difference in y between the two possible outcomes of the categorical variable holding x1 constant.

7 0

3 years ago

Can somebody please help me and how do you do this step by step and I need the formula for this please.

Ksivusya [100]

radius of ½ circle = d : 2

= 6in : 2 = 3in

Total area = Rectangle area + ½Circle area + Triangle area

= (l×w) + ½(π×r²) + (½×b×h)

= (10×6) + ½(π×3²) + (½ × (14-10) × 6)

= 60 + 14.14 + 12 = 86.14in

<h3 /><h3 /><h3>Answer : 86.14in</h3>

See the bold one in line 2 of total area, thats the formula of all shape.

8 0

3 years ago

What is the derivative of y=(4x+1)(1-x)^3

Rudik [331]

I am not so sure of this but I feel it would serve as hint

6 0

3 years ago

Futhe Mathematics <img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2

Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

$\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }$

We can write the numerator as ,

$\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }$

Recall the identity ,

$\longrightarrow (a-b)(a+b)=a^2-b^2$

Using this we have ,

$\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}$

Again , as we know that ,

$\longrightarrow sin^2\phi + cos^2\phi = 1$

Therefore we can rewrite it as ,

$\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}$

Again using the first identity mentioned above ,

$\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}$

Or else we can also write it using ,

$\longrightarrow cos2\phi = cos^2\phi - sin^2\phi$

Therefore ,

$\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}$

And we are done !

$\rule{200}{4}$

Additional info :-

Derivation of cos²x - sin²x = cos2x :-

We can rewrite cos 2x as ,

$\longrightarrow cos(x + x )$

As we know that ,

$\longrightarrow cos(y + z )= cosy.cosz - siny.sinz$

So that ,

$\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)$

On simplifying,

$\longrightarrow cos(x+x) = cos^2x - sin^2x$

Hence,

$\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}$

$\rule{200}{4}$

7 0

2 years ago