No it would be $481. 80 because of the 1.5. you ar3 supposed to do 7.30 times 44 and then equals 321.20 so you times that by 1.5
Answer:
To get the x-intercept we need the equation of the parabola;
the vertex form of the equation is given by:
y=a(x-h)^2+k
where:
(2,13) is the vertex:
Therefore;
y=a(x-2)^2+13
when x=0, y=5
Therefore the value of a will be:
5=a(0-2)^2+13
5-13=4a
4a=-8
a=-2
therefore the equation of the parabola will be:
y=-2(x-2)^2+13
y=-2x^2+8x+5
the x-intercept will be:
x=2-sqrt(7.5)
or
x=2+sqrt(7.5)
Step-by-step explanation:
Use the sum of cubes factoring rule
to transform the left hand side into the right hand side.
Throughout the entire process, the right hand side stayed the same.
On the last step, I used the pythagorean identity.
Let's see, if 1 pound = $1.54, let's times 1.54 by 200, the answer is $308, hope this helps
Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
