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mrs_skeptik [129]

3 years ago

5

PLSSSSSSSSSSS HELPPP MEEEEEE

1 answer:

Nimfa-mama [501]3 years ago

8 0

Answer:

A Fraction Bar

Step-by-step explanation:

Your Welcome!

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What is the distance between the points (2, 1) and(6, 7)?

icang [17]

Answer:

$\displaystyle d = 2\sqrt{13}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Coordinates (x, y)

<u>Algebra II</u>

Distance Formula: $\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (2, 1)

Point (6, 7)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(6 - 2)^2 + (7 - 1)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{4^2 + 6^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{16 + 36}$
[√Radical] Add: $\displaystyle d = \sqrt{52}$
[√Radical] Simplify: $\displaystyle d = 2\sqrt{13}$

3 0

3 years ago

A set of data has 50 observations. How many classes would you recommend?

nignag [31]

Answer:

6 classes

Step-by-step explanation:

If k is the number of classes and n is the number of observations, then for number of classes we should select the smallest k such that 2^k > n.

<u>We have n = 50 and:</u>

2^5 = 32 < 50
2^6 = 64 > 50

As per above described 2 to k rule, we are taking k = 6.

So 6 classes should be used.

6 0

3 years ago

Zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Kisachek [45]

Mmmmmmmmmmmmmmmmkkkkkkkkkkkkkkk

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7C%20%7Bx%7D%5E%7B2%7D%20%2B%203x%20%2B2%20%7C%20%3C%202x%20%2B%204" id="TexFormula1" titl

Snezhnost [94]

$\\ \tt\hookrightarrow |x^2+3x+2|$

Either

$\\ \tt\hookrightarrow x^2+3x+2$

$\\ \tt\hookrightarrow x^2+3x+2x$

$\\ \tt\hookrightarrow x^2+5x+6$

$\\ \tt\hookrightarrow (x+2)(x+3)$

$\\ \tt\hookrightarrow x$

Or

$\\ \tt\hookrightarrow x^2+3x+2$

$\\ \tt\hookrightarrow x^2+x-2$

$\\ \tt\hookrightarrow x^2+2x-x-2$

$\\ \tt\hookrightarrow (x+2)(x-1)$

$\\ \tt\hookrightarrow x$

So

$\\ \tt\hookrightarrow x\in (-3,1)$

7 0

2 years ago

Does one measure describe the data better than the others now?(mean-median)

puteri [66]

Mean is that. median is only at the middle. Not describe the set of numbers. Answer = Mean

3 0

3 years ago