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hjlf
3 years ago
7

A problem states: "There are 7 more girls than boys in a club. There are 23 members in the club in all. How many girls are there

in the club?"
Let g represent the number of girls.

Which expression represents the number of boys?




g−7

g + 7

7−g

g⋅7






​​ ​x=−4​

​​ ​x=−3​

​​ ​x=−2​

​x=−1
Mathematics
2 answers:
dlinn [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Number of boys = g - 7.

g - 7 + g = 23

2g = 30

g = 15.

The are 15 girls in the class.

Agata [3.3K]3 years ago
3 0

Answer: g-7

Step-by-step explanation:

g = number of girls in the club

b = number of boys in the club.

There are 7 more girls than boys in the club, therefore

g = b + 7            

Subtract 7 from each side.

g - 7 = b + 7 - 7

g - 7 = b

That is,

b = g - 7

Answer:  g - 7

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Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

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So, Q' = inflow - outflow = 0 - Q/100

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Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q  = -t/100 + c

Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c}  = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}

when t = 0, Q = 200 L × 1 g/L = 200 g

Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

2 = 200e^{(-t/100)}\\\frac{2}{200} =  e^{(-t/100)}

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

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Step-by-step explanation:

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