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kupik [55]
3 years ago
10

2x+1<9 I need help with this question

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

Answer: x<4

Step-by-step explanation: Let's solve your inequality step-by-step.

2x+1<9

Step 1: Subtract 1 from both sides.

2x+1−1<9−1

2x < 8

Step 2: Divide both sides by 2.

2x /2  <  8 /2

x<4

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Determine whether each sequence is arithmetic. If so, identify the common difference.
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Answer:

Options 1 and 4 are arithmetic

Step-by-step explanation:

Arithmetic means that you are adding or subtracting a number in a sequence.

For option 1, we are adding 2 every time.

-3 + 2 = -1   -1 + 2 = 1   1 + 2 = 3

For option 4, we are subtracting 7 every time.

32 - 7 = 25   25 - 7 = 18   18 - 7 = 11

Option 2 is geometric. Geometric means you are multiplying or dividing by a number in a sequence.

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Option 3 is actually quadratic. This is similar to a arithmetic, except instead, the amount added to the number is multiplied by 2 every time.

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2 years ago
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6 0
3 years ago
If Acot theta + Bcot theta =4 and
geniusboy [140]

Answer is: B

Step-by-step explanation: correct answer is B

b  

2

−a  

2

 

Given, acotθ+bcscθ=p

           bcotθ+acscθ=q

⇒p  

2

−q  

2

=(p−q)(p+q)

                   =[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

                   =[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

                   =(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

                   =(a  

2

−b  

2

)(cot  

2

θ−csc  

2

θ)

                   =(−1)(a  

2

−b  

2

)[∵csc  

2

θ−cot  

2

θ=1]

                   =(b  

2

−a  

2

)

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2 years ago
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