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OlgaM077 [116]
2 years ago
14

Given the point (-4,-6), what is the coordinate of the point reflected over the X-axis and Y-axis?

Mathematics
2 answers:
andrew11 [14]2 years ago
6 0

Answer:

(4, 6)

Step-by-step explanation:

In the question it says "<u>reflected over the X-axis and the Y-axis?</u>"

When reflected you get (4, 6)

The opposite of Negative is positive

Gemiola [76]2 years ago
4 0

Answer:

(4, 6)

Step-by-step explanation:

if it's a reflection then I believe it would just look exactly the same only with positive numbers

sorry if it's wrong, but hope it helps :)

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Does the system have no solution?​
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\mathrm{A)\:}-6

Step-by-step explanation:

Notice that in the second equation, the coefficient of y is 2 times greater than in the first. Therefore, by making the coefficient of x in the second equation 2 times greater than in the first, it's impossible to only isolate one variable.

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Find the equation of the line perpendicular to y =<br> 3x + 6 and containing the point (-9,-5).
neonofarm [45]

The equation of the line perpendicular to y =  3x + 6 and containing the point (-9,-5) is y = \frac{-1}{3}x - 8

<em><u>Solution:</u></em>

Given that line perpendicular to y =  3x + 6 and containing the point (-9, -5)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that <em>product of slopes of given line and slope of line perpendicular to given line is equal to -1</em>

Slope of given line \times slope of line perpendicular to given line = -1

3 \times \text{ slope of line perpendicular to given line }= -1

\text{ slope of line perpendicular to given line } = \frac{-1}{3}

Let us now find the equation of line with slope m = \frac{-1}{3} and containing the point (-9, -5)

Substitute m = \frac{-1}{3} and (x, y) = (-9, -5) in eqn 1

-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8

<em><u>Thus the required equation of line is:</u></em>

Substitute m = \frac{-1}{3} and c = -8 in eqn 1

y = \frac{-1}{3}x - 8

Thus the required equation of line perpendicular to given line is found

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