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LuckyWell [14K]
2 years ago
8

Factor the polynomial y2 + 12y -36

Mathematics
2 answers:
liberstina [14]2 years ago
5 0
(y+6)2 i’m pretty sure
Ivan2 years ago
5 0
I think it could be
(y-9) (y-3)
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5n + 3n<br> simplify each expression
Setler79 [48]

Answer: 8n

Step-by-step explanation: 5n + 3n

3 0
3 years ago
Does anyone know the answer?
iragen [17]
-60 djdjjeejjejdjdjdjdjejejejejdjdjjd
8 0
3 years ago
Please help!<br><br> For what value of x must ABCD be a​ parallelogram?<br><br> x=?
Vlad1618 [11]

Answer:

x=3

Step-by-step explanation:

For a shape to be a parallelogram, the angles that are across from one another have to be equal.

We can now find x by making both equations equal to each other and solving.

11x+1=13x-5

Solve.

11x+1=13x-5\\6=2x\\x=3

4 0
3 years ago
PLEASE HELP ASAP
Lesechka [4]

Answer:

A. f and h

Step-by-step explanation:

For a linear function the First Differences of the y-values must be a constant. i.e. if we take the difference between any two consecutive y values or values of f(x) it should be the constant. For this rule to work, x values must change by the same number every time, which is true for all three given functions.

For function f:

The values of f(x) are: 5,8,11,14

We can see the difference in consecutive two values is a constant i.e. 3, so the First Difference is the same. Hence, function f is a linear function.

For function g:

The values of g(x) are: 8,4,16,32

We can see the difference among two consecutive values is not a constant. Since the first differences are not the same, this function is not a linear.

For function h:

The values of h(x) are: 28, 64, 100, 136

We can see the difference among two consecutive values is a constant i.e. 36. Therefore, function h is a linear function.

5 0
3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
sdas [7]

Answer:

-15

Step-by-step explanation:

We proceed as follows;

In this question, we want to fill in the blank so that we can have the resulting expression expressed as the product of two different linear expressions.

Now, what to do here is that, when we factor the first two expressions, we need the same kind of expression to be present in the second bracket.

Thus, we have;

2a(b-3) + 5b + _

Now, putting -15 will give us the same expression in the first bracket and this gives us the following;

2a(b-3) + 5b-15

2a(b-3) + 5(b-3)

So we can have ; (2a+5)(b-3)

Hence the constant used is -15

8 0
3 years ago
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