Ask question

Ask question

All categories

3 years ago

7

Select the correct answer Which equation matches the function shown in the graph A.y=sin(x+pi) B. y=sin(x+pi/2) C.y=sin(x-pi) D.

y=(x-pi/2)

1 answer:

yan [13]3 years ago

5 0

Answer:

y= sin(x+pi/2)

Step-by-step explanation:

I graphed all of the answers with a calculator and this equation was the only one that had points above the 2 pi on the x axis.

You might be interested in

Find the interest<br> earned:<br> $26,000 for 36 months<br> at 7.5% annual<br> compound interest

stich3 [128]

Answer:

Interest = $6,300 (Approx.)

Step-by-step explanation:

Given:

Amount deposit (P) = $26,000

Number of month = 36 month

Number of year (n) = 36 / 12 = 3 year

Rate of interest (r) = 7.5% = 0.075

Find:

Interest earned

Computation:

Interest = p[(1+r)ⁿ-1]

Interest = 26,000[(1+0.075)³-1]

Interest = 26,000[(1.075)³-1]

Interest = 6,299.71

Interest = $6,300 (Approx.)

7 0

3 years ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

Is .849 greater than .90

Dmitry [639]

Answer:

NO it isnt.

Step-by-step explanation:

Go right of the decimal and throught the different place values. Since the number just right of the decimal is the highest place value, whichever number is greater, holds the greater value.

3 0

3 years ago

Read 2 more answers

Write the value of the underlined digit 7,270

RSB [31]

I am sorry but I do not see the underlined digit, but I will put it this way. 7 in the thousands place is worth 7000, 2 in the hundreds place is worth 200, 7 in the tens place is worth 70, and 0 in the ones place is worth 0.

Hope this helped!

Nate

3 0

3 years ago

A hospital parking lot charges $2.50 for the first hour or part thereof, and $1.25 for each additional hour or part thereof. A w

stepan [7]

12 times is the answer

3 0

3 years ago