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nata0808 [166]
3 years ago
9

12ab = 4 solve for a

Mathematics
2 answers:
WITCHER [35]3 years ago
8 0

Answer:

-3

Step-by-step explanation:

Levart [38]3 years ago
6 0
12ab=4
ab=4/12
ab=.3
a=.3/b
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Masja [62]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
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Fantom [35]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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Given a point A(-3,-1), it is dilated by some scale
Sidana [21]

Answer:

B' = (-3, -15)

Step-by-step explanation:

Given

A = (-3,-1)

A' = (-9,-3)

B = (-1,-5)

Required

Determine the coordinates of B'

Since A' is the image of A; we need to first calculate the scale factor using

A' = A * Scale\ factor

Make Scale Factor the subject

Scale\ Factor = \frac{A'}{A}

Substitute values for A' and A

Scale\ Factor = \frac{(-9,-3)}{(-3, -1)}

Factorize the numerator

Scale\ Factor = \frac{3 * (-3,-1)}{(-3, -1)}

Scale\ Factor = \frac{3 * 1}{1}

Scale\ Factor = 3

The coordinates of B' is then calculated as follows:

B' = B * Scale\ Factor

Substitute values for B and Scale Factor

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3 0
3 years ago
Can someone Please help me on this easy math problem
irina1246 [14]

Answer:

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8 0
3 years ago
What is the equation for the parabola that<br> has a focus at (-7, 6) and a directrix of x<br> 1?
Ne4ueva [31]

Answer:

Step-by-step explanation:

Parabola's equation is

y

=

1

16

(

x

−

7

)

2

+

1

and vertex is

(

7

,

1

)

.

Explanation:

Parabola is locus of a point which moves so that its distance from a given point calld focus and a given line ccalled directrix is always constant.

Let the point be

(

x

,

y

)

. Here focus is

(

7

,

5

)

and distance from focus is

√

(

x

−

7

)

2

+

(

y

−

5

)

2

. Its distance from directrix

y

=

−

3

i.e.

y

+

3

=

0

is

|

y

+

3

|

.

Hence equaion of parabola is

(

x

−

7

)

2

+

(

y

−

5

)

2

)

=

|

y

+

3

|

2

or

x

2

−

14

x

+

49

+

y

2

−

10

y

+

25

=

y

2

+

6

y

+

9

or

x

2

−

14

x

+

65

=

16

y

i.e.

y

=

1

16

(

x

2

−

14

x

+

49

−

49

)

+

65

16

or

y

=

1

16

(

x

−

7

)

2

+

65

−

49

16

or

y

=

1

16

(

x

−

7

)

2

+

1

Hence parabola's equation is

y

=

1

16

(

x

−

7

)

2

+

1

and vertex is

(

7

,

1

)

.

graph{(1/16(x-7)^2+1-y)((x-7)^2+(y-1)^2-0.15)((x-7)^2+(y-5)^2-0.15)(y+3)=0 [-12.08, 27.92, -7.36, 12.64]}

3 0
3 years ago
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