Anyone can help me please ?

Implement a sublinear running time complexity recursive function in Java public static long exponentiation (long x, int n) to ca

Charra [1.4K]

Answer:

Following are the code block in the Java Programming Language.

//define recursive function

public static long exponentiation(long x, int n) {

//check the integer variable is equal to the 0.

if (x == 0) {

//then, return 1

return 1;

}

//Otherwise, set else

else {

//set long data type variable

long q = exponentiation(x, n/2);

q *= q;

//check if the remainder is 1

if (n % 2 == 1) {

q *= x;

}

//return the variable

return q;

}

Explanation:

<u>Following are the description of the code block</u>.

Firstly, we define the long data type recursive function.
Then, set the if conditional statement and return the value 1.
Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.

4 0

2 years ago

A*=++a/6+b++ 3 if a=3,b=4

Vinil7 [7]

Answer:

$a=22.5$

Explanation:

Given

$a*=++a/6+b++3$

Required

The result when $a=3$ and $b=4$

Analyzing the given instruction

a*=(++a)/(6)+(b++3)

Single out and solve the expressions in bracket

(++a) = a -- When the ++ operator appears before an operand, it is called pre increment. meaning that the operation will be done before the operand will be incremented.

So: in this case: ++a = a

$b++3 = b + 3$

The operator, as used in that statement is the same as: b + 3.

So:

$a*=(++a)/(6)+(b++3)$

$a*=(a)/(6)+(b+3)$

$a*=(3)/(6)+(4+3)$

$a*=0.5+7$

$a*=7.5$

The above expression is calculated as:

$a=a*7.5$

So:

$a=3*7.5$

$a=22.5$

8 0

3 years ago

Write a program that declares and initializes a variable representing the weight in milligrams from the keyboard. The program di

Burka [1]

Answer:

weight = int(input("Enter weight in milligrams: "))

kilograms = int(weight / 1000000)

grams = int((weight - (kilograms * 1000000)) / 1000)

milligrams = weight - ((kilograms * 1000000) + (grams * 1000))

print("{} milligrams are equivalent to {} kilogram(s), {} gram(s), and {} milligram(s)".format(weight, kilograms, grams, milligrams))

Explanation:

*The code is in Python.

Ask the user to enter the weight and set it to the variable weight

Calculate the kilograms, divide the weight by 1000000 and cast the result to the int (If the weight is 1050042, kilograms would be 1050042/1000000 = 1)

Calculate the grams, subtract the kilograms from the weight, divide it by 1000 and cast the result to the int (If the weight is 1050042, grams would be int((1050042 - (1 * 1000000)) / 1000) = 50)

Calculate the milligrams, subtract the kilograms and grams from the weight (If the weight is 1050042, milligrams would be 1050042 - ((1 * 1000000) + (50 * 1000)) = 42)

Print the weight, kilograms, grams, and milligrams in the required format

3 0

2 years ago

The picture has the question on it

Bingel [31]

The answer is B. Row

4 0

2 years ago

Where can a user find out more information about a hardware or network failure that occurred on that particular pc?

dolphi86 [110]

In *nix the logs are usually in /var/log . They're usually restricted to privelidged access. In Windows, the Event Logs

7 0

2 years ago