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Natali5045456 [20]
3 years ago
9

What tool can help discover and report computer errors when you first turn on a computer and before the operating system is laun

ched?
Computers and Technology
2 answers:
Vlada [557]3 years ago
4 0

Answer:

a post diagnostic

Explanation:

Marysya12 [62]3 years ago
3 0

Answer:

post diagnostic Card

Explanation:

a post diagnostic card helps discover computer errors.

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What is basically the only thing that computers (microprocessors and prgrammable devices) understand?
horsena [70]

Answer:

Binary Code

Explanation:

All microprocessors and programmable devices understand is Binary Code. These are various combinations of 0's and 1's which when placed together in a sequence represent a set of instructions that the microprocessor can read and understand to complete complex tasks. There are various other programming languages to program these tasks in an easier to read syntax for the programmers themselves but they simply take the written code and convert it into Binary before sending it to the microprocessor.

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3 years ago
Cuál es la diferencia entre hackeo y crackeo
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Answer: El hackeo es el proceso de intrusión en los sistemas informáticos sin autorización para acceder a ellos, con buenos o malos propósitos, el cracking es la misma práctica aunque con intención delictiva.

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3 years ago
Which of the following is true about filters in microsoft excel database?
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C) Filters make it easier to find specific information in large databases.
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3 years ago
It is a well-researched fact that men in a restroom generally prefer to maximizetheir distance from already occupied stalls, by
Artyom0805 [142]

Answer:

The code below addresses the problem statement with appropriate comments for explanation.

Explanation:

public class Stall

{

public static void main(String[] args)

{

boolean[] arr = new boolean[10];

while(hasFreeSpots(arr))   // as long as there is a free slot

{

arr[position(arr)] = true;  

// position(arr) gets the position of slot a person would most likely enter at(view problem statement)

// setting that position true(position occupied) by arr[position(arr)]

System.out.println(stallView(arr));   // printing current state of the stall using 'X' and '_'

}

}

/**

* Find the empty position that is in the middle of the sub-array of largest group of empty spots

* @param arr an array of boolean values

* @return returns an an integer value. Optimal position to be occupied.

*/

public static int position(boolean[] arr)

{

int first = 0;   // first stores the starting position of "longest sequence of unoccupied places"

int last = 0;   // last stores the ending position of "longest sequence of unoccupied places"

int temp1 = 0;   // temp1 stores the starting position of "current sequence of unoccupied places"

int temp2 = 0; // temp2 stores the ending position of "current sequence of unoccupied places"

 

for(int i = 0; i < arr.length; i++)   // for each slot in the Stall

{    

if(!arr[i]) // if slot i is not occupied

{    

temp1 = i;   // store starting position of "current sequence of unoccupied places" in temp1

while(i < arr.length && !arr[i] )   // if i is a valid index and as long as this slot is not occupied increment i

{

i++;

}

// we break out of the loop either if i is invalid index(reached end of the array)

// or if the slot is occupied by a person already

temp2 = i;   // store ending position of "current sequence of unoccupied places" in temp2

if(Math.abs(first - last) < Math.abs(temp1 - temp2))

  // if current sequence is longer than longest sequence, update it

{

first = temp1;

last = temp2;    

}

}

}

return (first + last) / 2;   // return middle index of first and last

}

/**

* Checks if there are empty spots in an array, basically checks if there is a false boolean value

* thats representing an empty spot in an array

* @param arr the input array, of boolean values

* @return returns a boolean value, true if there are false elements inside the array

*/

public static boolean hasFreeSpots(boolean[] arr)

{

boolean rtn = true;   // initializing rtn to 'true'

for(int i = 0; i < arr.length; i++)   // for every slot in the Stall

{

if(!arr[i]){rtn = false;}   // sets rtn to false if a free spot found

}

return !rtn;   // returns true if a free spot found and returns false if no free spot found

}

/**

* X for true, _ for false. Representing occupied(X) and free stalls(_)

* @param arr a boolean array

* @return returns a string representation if the input

*/

public static String stallView(boolean[] arr)

{

String str = "";       // initializing str to be an empty String

for(int i = 0; i < arr.length; i++)   // for every slot in Stall

{

if(arr[i]){str += " X";}   // Add X to str if slot is occupied

else {str += " _";}           // prints _ to str if slot not occupied

}

return str;       // return str(pictorial representation of Stall with 'X', '_')

}

}

7 0
3 years ago
The coding system that has just two characters is called:
cupoosta [38]

Answer:

A. Binary

Definition:

Pertaining to a number system that has just two unique digits 0 and 1. - binary code

6 0
3 years ago
Read 2 more answers
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